The speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.
<h3>
Speed of the satellite</h3>
v = √(GM/r)
where;
- G is universal gravitation constant
- M is mass of Earth
- r is radius of the satellite
v = √(6.67 x 10⁻¹¹ x 5.98 x 10²⁴/3.57 x 6.37x 10³)
v = 1.32 x 10⁵ m/s
Thus, the speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.
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For the front glass of the car to get wet,
.
The given parameters:
- <em>Speed of the car, = Vc</em>
- <em>Speed of the rain, = 10 m/s</em>
The relative velocity of the car with respect to the falling rain is calculated as;

- If the speed of the car equals the speed of the rain, the rain will fall behind the car.
- If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.
- If the speed of the car is greater than speed of the rain, the rain will fall on the car.
Thus, for the front glass of the car to get wet,
.
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Answer:
Given that
P = RT/V + a/V²
We know that
H= U + PV
For T= Constant (ΔU=0)
ΔH= ΔU +Δ( PV)
ΔH= Δ( PV)
P = RT/V + a/V²
P V= RT + a/V
dH/dV = d(RT + a/V)/dV
dH/dV = - a/V²
So the expression of dH/dV

b)
In isothermal process
(ΔU=0)
Now by putting the all values


ΔH = 17.06 L.atm