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stellarik [79]
3 years ago
8

A 40 kg bike traveling down the road has a negative acceleration. What is true of the force? A. It is positive B. It doesn't exi

st C. It is negative D. It is zero
Help me pls.
Physics
2 answers:
Greeley [361]3 years ago
4 0

Answer:

C. It is negative

Explanation:

Per Newton's second law, the net force is the mass times the acceleration:

∑F = ma

If the acceleration is negative, the net force is negative.

S_A_V [24]3 years ago
3 0

Answer:

C. It is negative

Explanation:

As we know that mass of the bike is given as

m = 40 kg

now we know by Newton's law of motion

F = ma

here we know that

m = mass of the bike

a = acceleration of the bike

so here we will have

F = 40 (a )

now if the acceleration of the bike is in negative direction

then we will get a negative force on it as per above formula

so correct answer will be

C. It is negative

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Block m1 of mass 2m and velocity v0 is traveling to the right (+x) and makes an elastic head-on collision with block m2 of mass
Oksana_A [137]
1) In any collision the momentum is conserved

(2*m)*(vo) + (m)*(-2*vo) = (2*m)(v1') + (m)(v2')

candel all the m factors (because they appear in all the terms on both sides of the equation)

2(vo) - 2(vo) = 2(v1') + (v2') => 2(v1') + v(2') = 0 => (v2') = - 2(v1')

2) Elastic collision => conservation of energy

=> [1/2] (2*m) (vo)^2 + [1/2](m)*(2*vo)^2 = [1/2](2*m)(v1')^2 + [1/2](m)(v2')^2

cancel all the 1/2 and m factors =>

2(vo)^2 + 4(vo)^2 = 2(v1')^2 + (v2')^2 =>

4(vo)^2 = 2(v1')^2 + (v2')^2

now replace (v2') = -2(v1')

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Answer: (v1') = [√(2/3)]*(vo)




 
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3 years ago
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