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Olin [163]
3 years ago
3

a light ray hits a hard, opaque object. the angle at which the light ray bounces off the object depends on the smoothness of the

surface. the material the surface is made of. the angle at which the light hits the surface. the source of the light that hits the surface.
Physics
2 answers:
lana [24]3 years ago
8 0
<h3><u>Answer;</u></h3>

the angle at which the light hits the surface

<h3><u>Explanation;</u></h3>
  • A light ray hits a hard, opaque object. the angle at which the light ray bounces off the object depends <em><u>on the angle at which the light hits the surface.</u></em>
  • <em><u>The angle at which the light bounces off the surface is called the angle of reflection while the angle at which the light hits the surface is called the angle of incidence.</u></em>
  • According to the Laws of reflection; <em><u>when a ray hits a surface the angle of incidence is always equal to the angle of reflection.</u></em> Therefore, <em>the angle at which the light bounces off the surface depends on the angle of incidence.</em>

Sav [38]3 years ago
5 0
The correct answer that would best complete the given statement above would be the third statement. When a light ray hits a hard opaque object, the angle at which the light ray bounces off the object depends on <span>the angle at which the light hits the surface. Hope this answer helps. </span>
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Determine the slope of end a of the cantilevered beam. E = 200 gpa and i = 65. 0(106) mm4
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For E = 200 gpa and i = 65. 0(106) mm4,  the slope of end a of the cantilevered beam  is mathematically given as

A=0.0048rads

<h3>What is the slope of end a of the cantilevered beam?</h3>

Generally, the equation for the   is mathematically given as

A=\frac{PL^2}{2EI}+\frac{ML}{EI}

Therefore

A=\frac{10+10^2+3^2}{2*240*10^9*65*10^6}+\frac{10+10^3*3}{240*10^9*65*10^{-6}}

A=0.00288+0.00192=0.0048rads

A=0.0048rads

In conclusion,  the slope is

A=0.0048rads

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