Answer:
The mass of the water in the container is 139.187g
Explanation:
During this process there will not be lost heat. But heat lost of silver is equal to heat won of water
q(lost, silver) = q(gained, water)
-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)
⇒mass of silver = 63.3g
⇒Cpsilver = 0.24J/g °C
⇒initial temperature silver = 384.4 K
⇒ final temperature silver = 292.4 K
⇒mass of water = TO BE DETERMINED
⇒Cpwater = 4.184 J/g °C
⇒initial temperature water = 290.0 K
⇒final temperature = 292.4 K
-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)
-63.3 * 0.24 * (292.4-384.4) = mass * 4.184 * (292.4 - 290.0)
-1397.664 = mass * 0.24 *2.4
mass water = 139.187g
The mass of the water in the container is 139.187g
