Question

A sample of silver with a mass of 63.3 g is heated to a

Answer 1

Answer:

The mass of the water in the container is 139.187g

Explanation:

During this process there will not be lost heat. But heat lost of silver is equal to heat won of water

q(lost, silver) = q(gained, water)

-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)

⇒mass of silver = 63.3g

⇒Cpsilver = 0.24J/g °C

⇒initial temperature silver = 384.4 K

⇒ final temperature silver = 292.4 K

⇒mass of water = TO BE DETERMINED

⇒Cpwater = 4.184 J/g °C

⇒initial temperature water = 290.0 K

⇒final temperature = 292.4 K

-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)

-63.3 * 0.24 * (292.4-384.4) = mass * 4.184 * (292.4 - 290.0)

-1397.664 = mass * 0.24 *2.4

mass water = 139.187g

The mass of the water in the container is 139.187g