Magnitude of the force of tension: 139 N
Explanation:
The surface of the ramp here is assumed to be the positive x-direction.
To solve this problem and find the magnitude of the force of tension, we have to analyze only the situation along the x-direction, since the force of tension lie in this direction.
There are three forces acting along the x-direction:
- The force of tension,
, acting up along the plane - The force of friction,
, acting down along the plane - The component of the weight in the x-direction,
, acting down along the plane
We know that the magnitude of the weight is

So its x-component is

The net force along the x-direction can be written as

And therefore, since the net force is 98 N, we can find the magnitude of the force of tension:

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Answer:
Distance = 13.9 meters
Explanation:
Given the following data;
Maximum speed = 150 km/hr to meters per seconds = 150 * 1000/3600 = 41.67 m/s
Decelerating speed = 3m/s
To find the distance travelled with this speed;
Distance = maximum speed/decelerating speed
Distance = 41.67/3
Distance = 13.9 meters
Therefore, the bus would travel a distance of 13.9 meters before stopping.
Answer:
charge on each
Q1 = 2.06 ×
C
Q2 = 7.23 ×
C
when force were attractive
Q1 = 1.07 ×
C
Q2 = -1.39 ×
C
Explanation:
given data
total charge = 93.0 μC
apart distance r = 1.14 m
force exerted F = 10.3 N
to find out
What is the charge on each and What if the force were attractive
solution
we know that force is repulsive mean both sphere have same charge
so total charge on two non conducting sphere is
Q1 + Q2 = 93.0 μC = 93 ×
C
and
According to Coulomb's law force between two sphere is
Force F =
.........1
Q1Q2 = 
here F is force and r is apart distance and k is 9 ×
N-m²/C² put all value we get
Q1Q2 = 
Q1Q2 = 1.49 ×
C²
and
we have Q2 = 93 ×
C - Q1
put here value
Q1² - 93 ×
Q1 + 1.49 ×
= 0
solve we get
Q1 = 2.06 ×
C
and
Q1Q2 = 1.49 ×
2.06 ×
Q2 = 1.49 ×
Q2 = 7.23 ×
C
and
if force is attractive we get here
Q1Q2 = - 1.49 ×
C²
then
Q1² - 93 ×
Q1 - 1.49 ×
= 0
we get here
Q1 = 1.07 ×
C
and
Q1Q2 = - 1.49 ×
2.06 ×
Q2 = - 1.49 × 
Q2 = -1.39 ×
C
The distance the spring stretches is the answer.
I hope this helps.
Have a nice day.
Answer:
pitched sound
Explanation:
The shrillness of sound is known as Pitched Sound
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