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masya89 [10]
3 years ago
8

if the resistance of a car headlight is 15 ohm and the current through it is 0.60, what is the voltage across the headlight?

Physics
2 answers:
alex41 [277]3 years ago
5 0
Answer is 9 V you use Ohm’s Law to solve the problem
Strike441 [17]3 years ago
4 0

Answer:

9 volts (assuming 0.60 is in Amperes)

Explanation:

Recall that Ohms law can be expressed as

V = IR, where

V = voltage,

I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)

R = resistance (given as 15 ohm)

substituting the above values into the formula

V = IR

V = (0.6)(15)

V = 9 Volts

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Which statement best describes beaches? Beaches change over time as waves move further up the shore. Beaches are always changing
NemiM [27]

Answer:

I think the 1st statement is right.

Explanation:

Wind patterns doesn't stay the same.

Waves don't follow the same patterns.

Waves move further up the shore.

I didn't hear about "waves adding" before..so i guess 1st statement is right.

3 0
3 years ago
2. True or False Every sample of a pure substance has exactly the same composition
Marrrta [24]

Answer:

the correct answer is False

Explanation:

i hope its right

5 0
2 years ago
A tennis ball is thrown from a 25 m tall building with a zero initial velocity. At the same moment, another ball is thrown from
Nataly [62]

Answer:

The two balls meet in 1.47 sec.

Explanation:

Given that,

Height = 25 m

Initial velocity of ball= 0

Initial velocity of another ball = 17 m/s

We need to calculate the ball

Using equation of motion

s=ut+\dfrac{1}{2}gt^2+h

Where, u = initial velocity

h = height

g = acceleration due to gravity

Put the value in the equation

For first ball

s_{1}=0-\dfrac{1}{2}gt^2+25....(I)

For second ball

s_{2}=17t-\dfrac{1}{2}gt^2+0....(II)

From equation (I) and (II)

-\dfrac{1}{2}gt^2+25=17t-\dfrac{1}{2}gt^2+0

t=\dfrac{25}{17}

t=1.47\ sec

Hence, The two balls meet in 1.47 sec.

6 0
3 years ago
A car travels at a velocity of 8m/s for 16s . How far did it travel?
sertanlavr [38]

Answer:128m

Explanation:

8*16=128

7 0
3 years ago
Can a runner's average speed be different from her average velocity?
Tomtit [17]

Answer:

Yes

Explanation:

Since velocity is a vector, meaning it also relies on direction, the average speed can be different from her average velocity. An example would be if a runner turned around and ran backward after running 10 meters and returned to her starting point. If you took her average velocity of the entire trip it would actually be 0 but her average speed obviously would not be. This is why velocity can be negative but speed cannot.

5 0
2 years ago
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