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3 years ago

if the resistance of a car headlight is 15 ohm and the current through it is 0.60, what is the voltage across the headlight?

Physics

2 answers:

alex41 [277]3 years ago

5 0

Answer is 9 V you use Ohm’s Law to solve the problem

Strike441 [17]3 years ago

4 0

Answer:

9 volts (assuming 0.60 is in Amperes)

Explanation:

Recall that Ohms law can be expressed as

V = IR, where

V = voltage,

I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)

R = resistance (given as 15 ohm)

substituting the above values into the formula

V = IR

V = (0.6)(15)

V = 9 Volts

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Classify the following elements as alkine, alkine-earth, or transition metals based on their position on the periodic table

azamat

Explanation:

Iron transition metal

Potassium Alkaline metal

Strontium Alkaline earth metal

Platinum transition metal

The periodic table arranges elements based on their atomic numbers into periods and groups. Atomic number is the number of protons an atom contains.

On the periodic table:

Group IA is called Alkaline metal

Group IIA is the Alkaline earth metals

Group IIIA Boron family elements

Group VIIA Halogens

Group O Noble gases or inert gases.

Group IIIB to IIB Transition elements.

Running a check of the given elements on the periodic table will confirm answer.

Learn more:

Periodic table brainly.com/question/8543126

#learnwithBrainly

7 0

3 years ago

Volume equals 4÷3 times pi times nine to the power of 3

Tcecarenko [31]

Answer:

V=972π

The equation I used... V=4/3π(9)^3

4 0

2 years ago

Work is being done in which of these situations? all motions are at a constant velocity

fredd [130]

Where the force is not perpendicular to the path of motion

are you missing the the situations ?

7 0

3 years ago

What happens to the gravitational force between two masses when the distance between the masses is doubled?

vovangra [49]

Answer:

It decreases by a factor of 4

Explanation:

The gravitational force between two masses is given by

$F=\frac{Gm_1 m_2}{r^2}$

where

G is the gravitational constant

m1, m2 are the two masses

r is the separation between the two masses

In this problem, the distance between the masses is doubled, so

r' = 2r

Substituting into the equation, we see that the new force is

$F'=\frac{Gm_1 m_2}{(2r)^2}=\frac{1}{4}\frac{Gm_1m_2}{r^2})\frac{F}{4}$

So, the force decreases by a factor of 4.

6 0

3 years ago

a 2500 kg car going 35 m/a hits a 4000kg truck that is sitting still. What is the velocity of the truck if the car transfers all

lianna [129]

Answer:

Velocity of truck is 21.875 m/s.

Explanation:

Given:

Mass of the car (m) = 2500 kg

Initial speed of the car (u) = 35 m/s

Mass of the truck (M) = 4000 kg

Initial speed of the truck (U) = 0 m/s (Rest)

As per question, the total momentum of the car gets transferred to the truck.

Therefore, the final momentum of the car is 0.

Momentum is given as the product of mass and velocity.

So, if momentum becomes zero means the velocity becomes 0.

Therefore, final velocity of the car (v) = 0 m/s

Let the final velocity of truck be 'V' m/s.

Now, during collision, the total momentum remains conserved.

Initial momentum = Final momentum.

Initial momentum of car + Initial momentum of truck = Final momentum of car + Final momentum of truck.

⇒ $mu+MU=mv+MV\\\\2500\times 35+4000\times 0=2500\times 0+4000\times V\\\\87500+0=0+4000V\\\\4000V=87500\\\\V=\frac{87500}{4000}\\\\V=21.875\ m/s$

Therefore, the velocity of the truck is 21.875 m/s.

7 0

3 years ago