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3 years ago

The phrase terminal velocity can best be defined as

2 answers:

8 0

None of these are a good definition; a good definition would be "the maximum velocity that an object can fall at." however the best answer out go those is c. the constant velocity of some falling objects.

IgorLugansk [536]3 years ago

3 0

Answer:

c. the constant velocity of some falling objects.

Explanation:

When a body is dropped (or thrown up) vertically and only the force of gravity acts on it, it is said that the body carries a free fall motion. Free fall is a special case of uniformly varied rectilinear motion.

Therefore, the MRUV formulas will be applied, with a modification: The acceleration of the bodies in free fall is the acceleration of gravity represented by the letter g and is, on Earth, approximately equal to 9'8 m / s2.

An object that falls, initially gains speed. When gaining speed, the resistance force of the air will increase, which is nothing more than the result of collisions with the air molecules suffered by any object that travels through a layer of air. The greater the number of molecules with which it collides, the greater the resistance. Consequently, the air resistance depends on the speed of the falling object and its surface (its shape).

The object will continue to accelerate until the air resistance force is large enough to compensate for the force of gravity. At that time the object will continue to fall but will do so with constant speed (terminal velocity).

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When most chemical reactions take place, some ____ in the reactants must be broken, a process that requires energy.

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Answer:

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Choice-B is the correct one.

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Answer: Tech A is correct

Explanation:

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3 years ago

Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of

Pachacha [2.7K]

Answer:

The frequency changes by a factor of 0.27.

Explanation:

The frequency of an object with mass m attached to a spring is given as

$f$ = $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

where $f$ is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

$f_{n}$ = $\frac{1}{2\pi } \sqrt{\frac{k}{14m} }$

simplifying, we have

$f_{n}$ = $\frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }$

$f_{n}$ = $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$

if we divide this final frequency by the original frequency, we'll have

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ ÷ $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ x $2\pi \sqrt{\frac{m}{k} }$

==> 1/3.742 = 0.27

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3 years ago

A package is dropped from a helicopter moving upward at 15m/s. If it takes 10 s before the package strikes the ground, how high

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Answer:

A package is dropped from a helicopter moving upward at 15 m/s. If it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was released? (Disregard air resistance.)

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Note: The answer is given it's should be 1000 m ??

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Explanation:

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