Question

Which metal will form a compound with the general formula m2co3 when it combines with a carbonate ion

Answer 1

the answer is Lithium.

Answer 2

The question is incomplete, here is the complete question.

Which metal will form a compound with the general formula $M_2CO_3$ when it combines with a carbonate ion

A. Beryllium  

B. Aluminum

C. Calcium

D. Lithium

Answer: The metal that will form the given compound is lithium.

Explanation:

We are given:

A general chemical formula of carbonate, which is $M_2CO_3$

The given compound is an ionic compound.

Carbonate is a polyatomic ion having chemical formula $CO_3^{2-}$

Metal ion has a charge of +1.

For the given options:

Option A: Beryllium is the 4th element of the periodic table having electronic configuration of $1s^22s^2$

This element will loose 2 electrons to form $Be^{2+}$ ion.

Option B: Aluminium is the 13th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^1$

This element will loose 3 electrons to form $Al^{3+}$ ion.

Option C: Calcium is the 20th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^64s^2$

This element will loose 2 electrons to form $Ca^{2+}$ ion.

Option D: Lithium is the 3rd element of the periodic table having electronic configuration of $1s^22s^1$

This element will loose 1 electron to form $Li^{+}$ ion.

Hence, the metal that will form the given compound is lithium.