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3 years ago

NaBr + CaF2 - NaF + CaBrz es What coefficients are needed to balance the chemical equation?

Physics

1 answer:

Dovator [93]3 years ago

8 0

Answer:

4NaBr + 2CaF2 ---------- 4 NaF + 2CaBrz

Explanation:

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What is the acceleration of the box?

worty [1.4K]

Answer:

a=4,32m/s^2

Explanation:

Fnet = F1 - F2

= 12-1.2

= 10.8N

m=2.5kg

Fnet =ma

10.8=2.5a then divide both sides by 2.5 to get acceleration

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3 years ago

Marcus tells Sabrina that for the last few months, he has not been able to detect moderate heat or cold with his fingertips. Whi

hram777 [196]

Answer: The free ending nerves.

Explanation:

At our fingertips, we have a lot of sensory nerve endings, that give information about changes that occur at your skin.

Like touching something with a given texture, feeling pain, or noticing changes in temperature.

There are different types of nerve endings, particularly the ones responsible to detect pain, and temperature are the free nerve endings.

So Marcus may have the free nerve endings damaged.

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3 years ago

A exaplme of a spoiler in flight

Degger [83]

Answer:bad?

Explanation:

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2 years ago

Read 2 more answers

Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it

erica [24]

Answer:

2N/cm

Step-by-step explanation:

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

$F=kx$

where, $F$ is the force which is stretching or compressing the spring,

$k$ is the spring constant; and

$x$ is the distance the spring is stretched.

Substituting the given values to find the elastic constant $k$ to get:

$F=kx$

$4=k(2)$

$k=\frac{4}{2}$

$k=2$

Therefore, the elastic constant is 2 Newton/cm.

5 0

3 years ago

A wheel rotates about a fixed axis with an initial angular velocity of 13 rad/s. During a 8-s interval the angular velocity incr

____ [38]

Answer:

The number of revolutions is 44.6.

Explanation:

We can find the revolutions of the wheel with the following equation:

$\theta = \omega_{0}t + \frac{1}{2}\alpha t^{2}$

Where:

$\omega_{0}$ : is the initial angular velocity = 13 rad/s

t: is the time = 8 s

α: is the angular acceleration

We can find the angular acceleration with the initial and final angular velocities:

$\omega_{f} = \omega_{0} + \alpha t$

Where:

$\omega_{f}$ : is the final angular velocity = 57 rad/s

$\alpha = \frac{\omega_{f} - \omega_{0}}{t} = \frac{57 rad/s - 13 rad/s}{8 s} = 5.5 rad/s^{2}$

Hence, the number of revolutions is:

$\theta = \omega_{0}t + \frac{1}{2}\alpha t^{2} = 13 rad/s*8 s + \frac{1}{2}*5.5 rad/s^{2}*(8 s)^{2} = 280 rad*\frac{1 rev}{2\pi rad} = 44.6 rev$

Therefore, the number of revolutions is 44.6.

I hope it helps you!

4 0

3 years ago