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trasher [3.6K]
3 years ago
5

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid

has a mass of 4.3 × 104 kg, and the force causes its speed to change from 7600 to 5000 m/s. (a) What is the work done by the force? (b) If the asteroid slows down over a distance of 1.4 × 106 m determine the magnitude of the force.
I have part A, just need part B
A= -7.048E11 J
Physics
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

a)

- 7.04\times10^{11} J

b)

5.03\times10^{5} N

Explanation:

a)

m = mass of the asteroid = 43000 kg

v_{o} = initial speed of asteroid = 7600 m/s

v = final speed of asteroid = 5000 m/s

W = Work done by the force on asteroid

Using work-change in kinetic energy theorem

W = (0.5) m (v^{2} - v_{o}^{2})\\W = (0.5) (43000) (5000^{2} - 7600^{2})\\W = - 7.04\times10^{11} J

b)

F = magnitude of force on asteroid

d = distance traveled by asteroid while it slows down = 1.4 x 10⁶ m

Work done by the force on the asteroid to slow it down is given as

W = - F d\\- 7.04\times10^{11} = - F (1.4\times10^{6})\\F = 5.03\times10^{5} N

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