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4 years ago

Which is an example of a decomposer a hawk a mouse a flower or a mushroom

Physics

2 answers:

Alika [10]4 years ago

8 0

A mushroom is a decomposer

Anna71 [15]4 years ago

5 0

A mushroom definetly

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Jenni wants to start a print shop making specialty papers and cards. Which economic question has she answered?

Artemon [7]

I think it is Letter D, because she already said what to make

5 0

3 years ago

Read 2 more answers

When four people with a combined mass of 320 kg

ale4655 [162]

Each person is 80kg. 320/4

4 0

4 years ago

student built a simple heat engine that could lift masses. If the heat engine takes in 300 J of heat and loses 50 J to the envir

k0ka [10]

Answer:

So it will lift the mass by h = 17 m

Explanation:

As per energy conservation we know that

$Q_1 = W + Q_2$

here we know that

$Q_1 = 300 J$

$Q_2 = 50 J$

now we have

$W = 300 - 50$

$W = 250 J$

so work done by the engine is 250 J

now we have

$W = mgh$

$250 = 1.5 \times 9.81 \times h$

$h = 17 m$

4 0

3 years ago

A Doppler radar sends a pulse at

Rufina [12.5K]

Answer:

Explanation:

The problem is based on the concept of Doppler's effect of em wave .

Expression for apparent frequency can be given as follows

n = N x (V - v ) / ( V + v )

n is apparent frequency , N is real frequency , V is velocity of light and v is velocity of cloud.

n = 6 x 10⁹ ( 3 x 10⁸ - 8.52 ) / ( 3 x 10⁸ + 8.52 )

= 6 x 10⁹ ( 3 x 10⁸ ) ( 3 x 10⁸ + 8.52 )⁻¹

= 6 x 10⁹ ( 3 x 10⁸ ) ( 3 x 10⁸)⁻¹ ( 1 + 8.52/3 x 10⁸ )⁻¹

= 6 x 10⁹ ( 1 - 8.52/3 x 10⁸ )

= 6 x 10⁹ - 6 x 10⁹x 8.52/ (3 x 10⁸ )

= 6 x 10⁹ 1 - 170 .

So change in frequency = 170 approx.

7 0

3 years ago

Read 2 more answers

The perimeter of a sector of a circle is the sum of the two sides formed by the radii and the length of the included arc. A sect

snow_tiger [21]

Answer:

Length of the arc of this sector, l = 14 cm

Explanation:

It is given that, the perimeter of a sector of a circle is the sum of the two sides formed by the radii and the length of the included arc.

Perimeter of sector, P = 28 cm

Area of sector, $A=49\ cm^2$

According to figure,

2r + l = 28 ............(1)

Area of sector, $A=\dfrac{\theta}{360}\times \pi r^2$

Where, $\theta$ is in radian and $\theta=\dfrac{l}{r}$

Since, $1^{\circ}=\dfrac{\pi}{180}\ radian$

$A=\dfrac{l}{2\pi r}\times \pi r^2$

$r=\dfrac{98}{l}$

Put the value of r in equation (1) so,

$2\times (\dfrac{98}{l})+l=28$

$l^2-28l+196=0$

On solving above equation for l we get, l = 14 cm. So, the length of the arc of this sector is 14 cm. Hence, this is the required solution.

5 0

3 years ago