Question

What is an object's final velocity if it has an initial velocity of +12 meters/second with a constant acceleration of +14 meters/second2 and has traveled 48 meters in the +x direction?

Answer 1

We use the formula $v^2=u^2+2as$ to find the initial velocity

We have:
Initial velocity (u) = 12 m/s
Acceleration (a) = 14 m/s²
Distance (s) = 48 meters

We are looking to find the final velocity (v)
Substituting these values into the formula, we have:

v² = 12² + 2(14)(48)
v² = 144 + 1344
v² = 1488
v = √1488
v = 38.57 m/s