Why we use ethanol and salt in the titration ?

An inhibitor is added to an enzyme-catalyzed reaction at a concentration of 26.7 μM. The Vmax remains constant at 50.0 μM/s, but

fomenos

Using the Michaelis-Menten equation competitive inhibition, the Inhibition constant, Ki of the inhibitor is 53.4 μM.

<h3>What is the Ki for the inhibitor?</h3>

The Ki of an inhibitor is known as the inhibition constant.

The inhibition is a competitive inhibition as the Vmax is unchanged but Km changes.

Using the Michaelis-Menten equation for inhibition:

Kma = Km/(1 + [I]/Ki)

Making Ki subject of the formula:

Ki = [I]/{(Kma/Km) - 1}

where:

Kma is the apparent Km due to inhibitor
Km is the Km of the enzyme-catalyzed reaction
[I] is the concentration of the inhibitor

Solving for Ki:

where

[I] = 26.7 μM

Km = 1.0

Kma = (150% × 1 ) + 1 = 2.5

Ki = 26.7 μM/{(2.5/1) - 1)

Ki = 53.4 μM

Therefore, the Inhibition constant, Ki of the inhibitor is 53.4 μM.

Learn more about enzyme inhibition at: brainly.com/question/13618533

5 0

3 years ago

What has to happen to join two monosaccharide units into a disaccharide?

omeli [17]

A condensation reaction forming a glycosidic bond. so in other words a monosaccharide joining together to form a disaccharide.

5 0

3 years ago

Match each element to the number of electrons in its valence shell

blondinia [14]

Answer: Be= 2, C =4, Li = 1 and B=3

Explanation:

The valence shell can be define as the outermost shell of an atom that contains the valence electrons.

Beryllium (Be), electronic configuration; 1s2 2s2, = 2 electrons in its valence shell.

Carbon (C), electronic configuration; 1s2 2s2 2p2, = 4 electrons in its valence shell.

Lithium (Li), electronic configuration; 1s2 2s1 = 1 electron in its valence shell.

Boron (B) , electronic configuration; 1s2 2s2 2p1 = 3 electron in its valence shell.

6 0

3 years ago

In principle, the equilibrium in the dehydration of an alcohol could be shifted to the right be removal of water. Why is this ta

Trava [24]

Answer:

See explanation

Explanation:

In this case, we have to remember that if we want to remove water from the reaction vessel we have to heat the vessel. So, we can convert the liquid water into gas water and we can remove it from the vessel. In this case, the products of dehydration for both molecules are (E)-4-methylpent-2-ene and cyclohexene with boiling points of 59.2 ºC and 89 ºC respectively. The boiling point of water is 100 ºC, therefore if we heat the vessel the products and water would leave the system, and the products would be lost.

See figure 1

I hope it helps!