Answer:
See below
Explanation:
The half-cell reduction potentials are
Ag⁺(aq) + e⁻ ⇌ Ag(s) E° = 0.7996 V
Co²⁺(aq) + 2e⁻ ⇌ Co(s) E° = -0.18 V
To create a spontaneous voltaic cell, we reverse the half-reaction with the more negative half-cell potential.
We get the cell reaction
:
Anode: Co(s) ⇌ Co²⁺(aq) + 2e⁻
<u>Cathode: 2Ag⁺(aq) + 2e⁻ ⇌ 2Ag(s) </u>
Overall: Co(s) + 2Ag⁺ (aq) ⇌ Co²⁺(aq) + 2Ag(s)