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maxonik [38]
3 years ago
5

The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell

is the site of the reduction reaction. Type the half-cell reaction that takes place at the anode for the cobalt-silver voltaic cell. Indicate the physical states of atoms and ions using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) for an aqueous solution. Do not include phases for electrons. Express your answer as a chemical equation.
Chemistry
1 answer:
SashulF [63]3 years ago
3 0

Answer:

See below  

Explanation:

The half-cell reduction potentials are

 Ag⁺(aq) +   e⁻ ⇌ Ag(s)     E° =  0.7996 V

Co²⁺(aq) + 2e⁻ ⇌ Co(s)     E° = -0.18      V

To create a spontaneous voltaic cell, we reverse the half-reaction with the more negative half-cell potential.

We get the cell reaction :

Anode:     Co(s)                 ⇌ Co²⁺(aq) + 2e⁻

<u>Cathode: 2Ag⁺(aq) +   2e⁻ ⇌ 2Ag(s)                  </u>        

Overall:  Co(s) + 2Ag⁺ (aq) ⇌ Co²⁺(aq) + 2Ag(s)

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Answer:

Answer is option B . This is because water is said to be highly permeable to the underground soil and thus nourishes it , whereas capillary action will make the water flow upward sllowly , but the water is going underground so it is permeability. Also soil is porous too , but that's only if the water is in the soil , here the water is caused to go underground by some force , so porosity isnt the right option

Explanation:

3 0
3 years ago
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A weak acid (ha) has a pka of 4.001. If a solution of this acid has a ph of 4.110, what percentage of the acid is not ionized? (
OverLord2011 [107]

99.9224 % of the acid is not ionized.

____HA + H₂O ⇌ A⁻ + H₃O⁺

I: ___<em>c</em> ________0 ____0  

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E: <em>c</em>(1-α) _______α<em>c</em> ___α<em>c </em>

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7 0
3 years ago
If 5g of H2 are reacted with excess CO, how many grams of CH3OH are produced, based on a yield of 86%?
Cerrena [4.2K]

Answer: 34.4 g

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of hydrogen}=\frac{5g}{2g/mol}=2.5moles

As CO is in excess, H_2 is the limiting reagent and thus it will limit the formation of products.

CO+2H_2\rightarrow CH_3OH

According to stoichiometry:

2 moles of hydrogen produce = 1 mole of CH_3OH

2.5 moles of hydrogen produce = \frac{1}{2}\times 2.5=1.25 moles of CH_3OH

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Thus 34.4 g of CH_3OH is produced.

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Answer:

B

Explanation:

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