Answer:
B & A
Explanation:
A Compound consists of two or more atoms from different elements, that are chemically bound together.
A electron carries a negative charge, because it is found in the electron cloud
If your wondering too, A proton carries A Positive charge.
Then it is called PARTIAL IONIC BOND.
Thermal conductivity of a substance affects it's ability to heat or to be heated by its surroundings.
This happens because as the temperature increases the kinetic energy which is possessed by the molecules also increases as there is increased collision between the molecules which leads to increase in the thermal conductivity of substance.
<h3>What is thermal conductivity?</h3>
It is defined as the ability of a substance to provide conduction of heat.Higher the thermal conductivity of a substance, more rapidly it will conduct heat and lower values of thermal conductivity depict low rate of conduction of heat.
Thermal conductivity depends on 3 factors namely,temperature, moisture content and density.
Learn more about thermal conductivity,here:
brainly.com/question/10542041
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Answer:
![Q_{sln}=-3219.25 J](https://tex.z-dn.net/?f=Q_%7Bsln%7D%3D-3219.25%20J)
Explanation:
Hello there!
In this case, for this calorimetry problem, it is possible for us to infer that the heat of the reaction of dissolution of KNO3 is absorbed by the solution composed by the former and water so that we can write:
![Q_{rxn}=-Q_{sln}](https://tex.z-dn.net/?f=Q_%7Brxn%7D%3D-Q_%7Bsln%7D)
Thus, given the mass, specific heat and temperature of the solution, we plug in the data to obtain the heat absorbed, by the reaction:
![Q_{rxn}=-m_{sln}C_{sln}\Delta T _{sln}\\\\Q_{rxn}=-(13.3+213)g(4.184\frac{J}{yg\°C} )(19.60-23.00)\°C\\\\Q_{rxn}=3219.25J](https://tex.z-dn.net/?f=Q_%7Brxn%7D%3D-m_%7Bsln%7DC_%7Bsln%7D%5CDelta%20T%20_%7Bsln%7D%5C%5C%5C%5CQ_%7Brxn%7D%3D-%2813.3%2B213%29g%284.184%5Cfrac%7BJ%7D%7Byg%5C%C2%B0C%7D%20%29%2819.60-23.00%29%5C%C2%B0C%5C%5C%5C%5CQ_%7Brxn%7D%3D3219.25J)
Also, we can say the the heat released by the solution was -3219.25 J.
Best regards!