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Elina [12.6K]
3 years ago
5

Instructions:Select the correct answer. What falls in the gray area between living and nonliving things? bacteria mold virus yea

st
Physics
2 answers:
viva [34]3 years ago
6 0
Virus. it's only living when it enters a host's body as it's a parasitic organism
Scilla [17]3 years ago
3 0

Answer:

virus

Explanation:

Viruses are considered organisms at the limit of life. On the one hand they resemble organisms that have genes and evolve by natural selection and reproduce by creating multiple copies of themselves. However, they lack cellular structure, which is the pillar of life. It can only multiply within the cells of other organisms.

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Three strategies which local municipality is implementing in addressing the issue
siniylev [52]

Having and drinking hygienic water is human right and is vital to life. The water should be tested, treated and filtered to remove any contaminants that can lead do sickness. Some of the strategies in which local municipality is implementing in <span>addressing the topic of lack of clean water are:
1. </span><span>Good monitoring of the water supplies
2. Desalination – </span>this is removal of mineral components from saline water especially salt. The procedure is more expensive but is a way to reuse water <span>
<span>3. Campaign for more proficient and more wisely usage of the water in order to make the people conscious of the fact how important the natural resource water is.</span></span>

5 0
3 years ago
My questions are in the picture: <br>Please help.
frutty [35]

Answer:

a.)

I.) Open system

II.) Closed system

b.)

The total momentum of the object and earth system stay the same as the object fall toward the earth

The kinetic energy of the object increases as the object falls toward the earth.

Explanation:

a.)

I.) The system containing only the object is an open system because of the influence of external forces and presence of matters. External forces in this scenario means gravitational force acting on the object. And air is the matter that has influence on the object.

II.) The system containing only the object and earth is a closed system. Because in a closed system, there are no external dissipative forces acting on it. Universe is a closed system. And the mechanical energy of a close system is conserved. The mechanical energy will remain constant. In other words, it will not change (become more or less). This is called the Law of Conservation of Mechanical Energy.

b.) The total momentum of the object and earth system stay the same as the object fall toward the earth. Because momentum will always be conserved.

The kinetic energy of the object increases as the object falls toward the earth. When the object was initially at rest, kinetic energy equals zero

8 0
3 years ago
Sometime around 2024, astronomers at the European Southern Observatory hope to begin using the E-ELT (European Extremely Large T
soldier1979 [14.2K]

Answer:

Expression for angular resolution is;

θ = 1.22π/d

a) 0.85 light year

b) 2.15 x 10³ m

Explanation:

See attached images

5 0
4 years ago
Please help I'm stuck on these 2 problems would help so much!! 10 POINTS<br><br> Thanks!
bekas [8.4K]
Its C because the circuit is connected with battery and light bulb.

4 0
4 years ago
At time t=0 a 2150 kg rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. This forc
amm1812

Explanation:

Given that,

Mass of the rocket, m = 2150 kg

At time t=0 a rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. The force is given by equation :

F=At^2

Here F = 888.93 N when t = 1.25 s

(c) We can find the value of A first as :

F=At^2\\\\A=\dfrac{F}{t^2}\\\\A=\dfrac{888.93}{(1.25)^2}\\\\A=568.91\ N/s^2

The value of A is 568.91\ N/s^2.

(a) Let J is the impulse does the engine exert on the rocket during the 4.0 s interval starting 2.00 s after the engine is fired. It is given in terms of force as :

J=\int\limits {F{\cdot} dt}

Limits will be from 2 s to 2+ 4 = 6 s

It implies :

J=\int\limits^6_2 {At^2{\cdot} dt}\\\\J=A\int\limits^6_2 {t^2{\cdot} dt}\\\\J=A\dfrac{t^3}{3}|_2^6\\\\J=568.91\times \dfrac{1}{3}\times (6^3-2^3)\\\\J=39444.42\ Ns

(b) Impulse is also equal to the change in momentum as :

J=m\Delta v\\\\\Delta v=\dfrac{J}{m}\\\\\Delta v=\dfrac{39444.42}{2150}\\\\\Delta v=18.34\ m/s

Hence, this is the required solution.

5 0
3 years ago
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