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nevsk [136]
3 years ago
14

What is the solubility of m(oh)2 in a 0.202 m solution of m(no3)2? ksp 4.45*10^-12?

Chemistry
1 answer:
umka2103 [35]3 years ago
6 0

<span>M(NO</span>₃<span>)</span>₂<span> fully separates into M</span>²⁺<span> and NO</span>₃<span> </span>²⁻<span> </span><span>and M(OH)</span>₂<span> partially separates as <span>M</span></span>²⁺<span><span> and 2OH</span></span>⁻

<span>M(NO</span>₃<span>)</span>₂<span><span>     </span>→        M</span>²⁺<span>      +          2NO</span>₃²⁻

<span>0.202 M                 0.202 M</span>

 

<span>     M(OH)</span>₂<span>(s)        ↔        <span>M</span></span>²⁺<span><span> (aq) +          2OH</span></span>⁻<span><span>(aq)</span></span>

<span>I                                         -                            -</span>

<span>C   -X                                +X                        +2X</span>

<span>E                                        X                          2X</span>

 

<span>Ksp                  =          [M</span>²⁺<span> (aq)] [OH</span>⁻<span>(aq)]</span>²

4.45 * 10∧-12        =          (0.202 + X ) (2X)²

Since X is very small, (0.202 + X ) = 0.202

<span>4.45 * 10<span>-12        </span>=          0.202 * 4X</span>²

<span>            X          =          2.347 </span>× 10∧-6 M

Hence the solubility of <span>M(OH)2 is 2.347 </span>× 10∧-6 M

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