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3 years ago

50 POINTS

Physics

2 answers:

mylen [45]3 years ago

8 0

Answer:

The correct answer is: B area = area

Explanation:

Vikki [24]3 years ago

3 0

Answer:

The correct answer is: B area = area

Explanation: You can solve this problem through the use of laws of Kepler's planetary motion. There are Kepler the laws ( 3 of them) In this exercise, we will use the second law. According to this law, a line segment joining a planet and the sun sweeps out areas is equal to that during the equal intervals of time

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A mass of mercury occupies 0.750 L. What volume would an equal mass of ethanol occupy? The density of mercury is 13.546 g/mL, an

melamori03 [73]

Answer:

Ve=12876.43mL : Ethanol volume

Explanation:

We apply the formula to calculate the density:

ρ= $\frac{m}{V}$ Formula (1)

Where:

ρ:Density in g/mL

m: mass in g (grams)

V= Volume in ml (milliliters)

We know the following data:

1L= 1000mL

Vm=Volume of mercury:VHg=0.750 L*1000mL/L=750mL

ρ-m=Density of mercury =13.546 g/mL

ρ-e: density of ethanol is 0.789 g/mL

$m_{m} =m_{e}$

Development of the problem:

In formula 1 We replace the known data for the mercury :

ρ-m= $\frac{m_{m} }{V_{m} }$

$13.546 \frac{g}{mL} =\frac{m_{m} }{750mL}$

$m_{m}=13.546 \frac{g}{mL}*750mL$

$m_{m} =10159.5 g$

We know that $m_{e} =m_{m} =10159.5 g$ , then, We replace the known data for the ethanol In formula 1:

ρ-e= $\frac{m_{e} }{V_{e} }$

$0.789 \frac{g}{mL} =\frac{10159.5g}{V_{e} }$

$Ve=\frac{10159.5 g}{0.789 \frac{g}{mL}}$

$Ve=12876.43mL$

8 0

3 years ago

ERCRSOVOS - Table tennis footwork that is useful in this moment to cover a large distance quickly (SCRAMBLED)PE)

nata0808 [166]

Answer:

it's CROSSOVER I knew it because I'm a table tennis player

4 0

2 years ago

17)

lina2011 [118]

17 , d . because a force is being applied but it is not moving .

19 . is c .

20 .b .

21 . d .

31 . d .

4 0

3 years ago

A basketball of mass 0.608 kg is dropped from rest from a height of 1.37 m. It rebounds to a height of 0.626 m.

kenny6666 [7]

Answer:

a) $|\Delta E|=4.58\: J$

b) $F=61.90\: N$

Explanation:

We can use conservation of energy between these heights.

$\Delta E=mgh_{2}-mgh_{1}=mg(h_{2}-h_{1})$

$\Delta E=0.608*9.81(0.6026-1.37)$

Therefore, the lost energy is:

$|\Delta E|=4.58\: J$

The force acting along the distance create a work, these work is equal to the potential energy.

$W=\Delta E$

$F*d=mgh$

Let's solve it for F.

$F=\frac{mgh}{d}$

$F=\frac{0.608*9.81*1.37}{0.132}$

Therefore, the force is:

$F=61.90\: N$

I hope is helps you!

6 0

2 years ago

What are 90 percent of the stars in space called?

Naddik [55]

Yes there called stars because when a star in space goes nova it shines in the sky like a little twinkle because it far away the sun is also a star too.<span />

6 0

3 years ago