Let f and $\lambda$ are frequency and the wavelength of the wave respectively. The relationship between the time period and the frequency is given by :

$f=\dfrac{1}{T}$

$f=\dfrac{1}{0.01}$

f = 100 Hz

The wavelength of a wave is given by :

$\lambda=\dfrac{c}{f}$

$\lambda=\dfrac{3\times 10^8}{100}$

$\lambda=3\times 10^6\ m$

So, the frequency and wavelength of the carrier wave are 100 Hz and $3\times 10^6\ m$ respectively. Hence, the correct option is (c).

6 0

2 years ago

An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 2530 km. When the astronaut jumps upwa

Natali [406]

Answer:

1.38*10^18 kg

Explanation:

According to the Newton's law of universal gravitation:

$F=G*\frac{m_a*m_p}{r^2}$

where:

G= Gravitational constant (6.674×10−11 N · (m/kg)2)

ma= mass of the astronaut

mp= mass of the planet

$F=m_a.a\\(v_f )^2=(v_o)^2+2.a.\Delta y\\\\a=\frac{(v_f)^2-(v_o)^2}{2.\Delta y}\\\\a=\frac{(0)^2-(4.29m/s)^2}{2.0.64m}=14.38m/s^2\\\\F=m_a*14.38m/s^2$

so:

$m_a*14.38m/s^2=(6.674*10^{-11}N.(m/kg)^2)*\frac{m_a.m_p}{(2.530*10^3m)^2}\\m_p=\frac{14.38m/s^2(2.530*10^3m)^2}{(6.674*10^{-11}N.(m/kg)^2)}\\\\m_p=1.38*10^{18}kg$

7 0

3 years ago

You place a box weighing 200.2 N on a inclined plane that makes a 37.1 angle with the horizontal. Compute the component of the g

salantis [7]

Answer:

141.56 N.

Explanation:

Data given:

Weight of the box= 200.2 N

Angle with the horizontal= 37.1°

Solution;

Gravitational force on the box, $F_g$ = weight of the box

= 200.2 N

Component of gravitational force along plane = $F_g * sin$ ( ∅ )

= W * (sin∅)

= (200.1) * sin (37.1°)

= 141.56 N

8 0

2 years ago