Question

A student hooks up a voltmeter and an ammeter in a circuit to find the resistance of a light bulb. The ammeter read 3 amps and the voltmeter reads 6 volts. What is the resistance of the light bulb?

Answer 1

Answer:

$2\Omega$

Explanation:

(Assuming the cell in the circuit has 0 internal resistance)

Ohm's Law is given as:

$V=IR$

Voltage is Current multiplied by Resistance.

We can rearrange this formula to give us:

$R=\frac{V}{I}$

Now we can plug in our values

$R=\frac{6}{3}=2\Omega$

Answer 2

I= 3A

V= 6V

R=?

V=IR

R=V/I

R=6/3

Therefore R = 2ohms

Hope this will help u mate :)