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Sauron [17]
3 years ago
5

A student hooks up a voltmeter and an ammeter in a circuit to find the resistance of a light bulb. The ammeter read 3 amps and t

he voltmeter reads 6 volts. What is the resistance of the light bulb?
Physics
2 answers:
yuradex [85]3 years ago
7 0

Answer:

2\Omega

Explanation:

(Assuming the cell in the circuit has 0 internal resistance)

Ohm's Law is given as:

V=IR

Voltage is Current multiplied by Resistance.

We can rearrange this formula to give us:

R=\frac{V}{I}

Now we can plug in our values

R=\frac{6}{3}=2\Omega

Ad libitum [116K]3 years ago
7 0

I= 3A

V= 6V

R=?

V=IR

R=V/I

R=6/3

Therefore R = 2ohms

Hope this will help u mate :)

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it is idea being transmitted by the sender to the receiver. it includes three aspects-content, structure, and style​
Diano4ka-milaya [45]

Answer: The options are not given,

Here are the options.

A. channel

B. feedback

C. message

D. sender​

The correct option is C

MESSAGE.

Explanation:

It is message because it is written or verbal or recorded words or communication or ideas transmitted by the sender to the receiver.

It include three aspects, content, structure and style.

The content entails the information and communication, how the information is important, useful and can be read to comprehend.

The structure of a message entails the tone .

The style include how the sender compose and write the message.

4 0
3 years ago
A 25.0kg girl pushes a 50.0kg boy so that he accelerates at 4.00m/s2. What is the force of the boy on the girl? A. 200N B. 100N
Fynjy0 [20]

Answer:

a

Explanation:

so the answer is 200N

and I hope it is correct

8 0
3 years ago
An airplane flies 1000 miles in 2 hours. What is its average speed in miles per hour?
OLEGan [10]

Answer:

500km per hour

Explanation:

if in 2 hours the airplane flies 1000 km then 1000 divided by 2 is 500km per hour.

5 0
3 years ago
Two basketballs of equal mass are rolling toward each other at constant velocities. The first basketball (B1) has a velocity of
slamgirl [31]

v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

<u>Explanation:</u>

Velocity of B₁ = 4.3m/s

Velocity of B₂ = -4.3m/s

For perfectly elastic collision:, momentum is conserved

m_1v_1 + m_2v_2 = m_1v'_1 + m_2v'_2

where,

m₁ = mass of Ball 1

m₂ = mass of Ball 2

v₁ = initial velocity of Ball 1

v₂ = initial velocity of ball 2

v'₁ = final velocity of ball 1

v'₂ = final velocity of ball 2

The final velocity of the balls after head on elastic collision would be

v'_2 = \frac{2m_1}{m_1+m_2} v_1 - \frac{m_1-m_2}{m_1+m_2} v_2\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} v_1 + \frac{2m_2}{m_1+m_2} v_2

Substituting the velocities in the equation

v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

If the masses of the ball is known then substitute the value in the above equation to get the final velocity of the ball.

5 0
3 years ago
What is a non-example of Newton's 3rd law of motion?
kirill [66]

Answer:

Unbalanced forces are not examples of Newton's third law because not all opposite reactions are unbalanced forces.

Explanation:

4 0
3 years ago
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