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Sauron [17]
3 years ago
5

A student hooks up a voltmeter and an ammeter in a circuit to find the resistance of a light bulb. The ammeter read 3 amps and t

he voltmeter reads 6 volts. What is the resistance of the light bulb?
Physics
2 answers:
yuradex [85]3 years ago
7 0

Answer:

2\Omega

Explanation:

(Assuming the cell in the circuit has 0 internal resistance)

Ohm's Law is given as:

V=IR

Voltage is Current multiplied by Resistance.

We can rearrange this formula to give us:

R=\frac{V}{I}

Now we can plug in our values

R=\frac{6}{3}=2\Omega

Ad libitum [116K]3 years ago
7 0

I= 3A

V= 6V

R=?

V=IR

R=V/I

R=6/3

Therefore R = 2ohms

Hope this will help u mate :)

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