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3 years ago

5

A student hooks up a voltmeter and an ammeter in a circuit to find the resistance of a light bulb. The ammeter read 3 amps and t

he voltmeter reads 6 volts. What is the resistance of the light bulb?

2 answers:

yuradex [85]3 years ago

7 0

Answer:

$2\Omega$

Explanation:

(Assuming the cell in the circuit has 0 internal resistance)

Ohm's Law is given as:

$V=IR$

Voltage is Current multiplied by Resistance.

We can rearrange this formula to give us:

$R=\frac{V}{I}$

Now we can plug in our values

$R=\frac{6}{3}=2\Omega$

Ad libitum [116K]3 years ago

7 0

I= 3A

V= 6V

R=?

V=IR

R=V/I

R=6/3

Therefore R = 2ohms

Hope this will help u mate :)

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Answer:

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Explanation:

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2 years ago

A train 471 m long is moving on a straight track with a speed of 75.1 km/h. The engineer applies the brakes at a crossing, and l

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Answer:

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Explanation:

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2 years ago

Describe how the kidney and bladder work together to remove waste from the body. (2 points)

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3 years ago

Read 2 more answers

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3 years ago

Two circular coils are concentric and lie in the same plane. The inner coil contains 170 turns of wire, has a radius of 0.0095 m

PIT_PIT [208]

Answer:

Current in outer circle will be 15.826 A

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We have given number of turns in inner coil $N_I=170$

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Radius of outer circle $r_o=0.015m$

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For net magnetic field current must be in opposite direction as in inner circle

We know that magnetic field is given due to circular coil is given by

$B=\frac{N\mu _0I}{2r}$

For net magnetic field zero

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So $\frac{170\times \mu _0\times 8.9}{2\times 0.0095}=\frac{150\times \mu _0I_O}{2\times 0.015}$

$I_O=15.92A$

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3 years ago