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IRINA_888 [86]
2 years ago
14

Give an explanation for the order of reactivity observed for the three saturated alkyl halides with ag+

Chemistry
1 answer:
stepan [7]2 years ago
4 0
<span>There are 3 prime, 2 prime, and 1 prime carbocations that form in the reaction. SN1 reactions favor them in the order of 3, 2, then 1.</span>
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dentify the correct formula for the following ionic compounds. - sodium chloride - magnesium chloride - calcium oxide - lithium
andrey2020 [161]

Explanation:

The chemical formula of an ionic compound can be written by using the symbols of the respective cations and anions.

The overall charge on the molecule should be zero.

Hence, the total charge of cations=total charge of anions.

The symbols of the given molecules are shown below:

sodium chloride  ---- NaCl

magnesium chloride ---MgCl_2

calcium oxide ---- CaO

lithium phosphide----Li_3P

aluminum sulfide ----- Al_2S_3

calcium nitride---- Ca_3N_2

5 0
3 years ago
How many molecules of O2 will be required to produce 28.8 g of water?
Mrac [35]
I think 1.67 x 10^20
5 0
3 years ago
What does stoichiometry use to relate moles of one molecule to moles of
Shkiper50 [21]
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6 0
1 year ago
What are the correct coefficients for each reactant and product when this equation is balanced? Make sure to select the correct
Mars2501 [29]

Answer: 44

Explanation:

5 0
3 years ago
How many particles are in a 151 g sample of Li2O?
neonofarm [45]

Answer:

3.052 × 10^24 particles

Explanation:

To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)

The mass of Li2O given in this question is as follows: 151grams.

To convert this mass value to moles, we use;

moles = mass/molar mass

Molar mass of Li2O = 6.9(2) + 16

= 13.8 + 16

= 29.8g/mol

Mole = 151/29.8g

mole = 5.07moles

number of particles (nA) of Li2O = 5.07 × 6.02 × 10^23

= 30.52 × 10^23

= 3.052 × 10^24 particles.

4 0
2 years ago
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