Question

A ball is thrown vertically upward with an initial velocity of 23.6 meters per second. What is the maximum height reached by the ball? Please include your answer with a unit symbol.

Answer 1

Answer:

Maximum height attained by the ball will be h = 28.416 m

Explanation:

We have given initial speed of the ball u = 23.6 m /sec

At maximum height velocity will be zero so final velocity v = 0 m/sec

Acceleration due to gravity $g=9.8m/sec^2$

From law of motion we know that $v^2=u^2-2gh$

$0^2=23.6^2-2\times 9.8\times h$

h = 28.416 m

So maximum height attained by the ball will be h = 28.416 m