Answer: <em><u>A</u></em><em><u>. The current in a 60-Watt bulb plugged into a 120-Volt outlet is 0.5 A. </u></em>
<em><u>I = P / V = (60 W) / (120 V) = 0.5 A</u></em>
<h3>
<u>For each problem, use the P = V • I equation to solve for the unknown quantity. In a, b, and e, the unknown quantity is current (I); and in c and d, the unknown quantity is power (P).</u></h3>
Other answers:
b. The current in a 120-Watt bulb plugged into a 120-Volt outlet is 1.0 A.
I = P / V = (120 W) / (120 V) = 1.0 A
c. The power of a saw that draws 12 amps of current when plugged into a 120-Volt outlet is 1440 W.
P = V • I = (120 V) • (12 A) = 1440 W
d. The power of a toaster that draws 6 amps of current when plugged into a 120-Volt outlet is 720 W.
P = V • I = (120 V) • (6 A) = 720 W
e. The current in a 1000-Watt microwave when plugged into a 120-Volt outlet is 8.3 A.
I = P / V = (1000 W) / (120 V) = 8.3 A
Answer:
45 s
Explanation:
To find the time it takes to stop, we first find the deceleration, a of the car from
v² = u² + 2as and a = (v² - u²)/2s were v = final velocity of car = 0 mph = 0 m/s, u = initial velocity of car = 30 mph = 30 × 1609.34 ft ÷ 3600 s = 13.41 ft/s and s = distance = 300 ft. Substituting the values into a, we ave
a = (v² - u²)/2s = (0² - 13.41²)/2×300 = -0.3 ft/s²
We then find the time for this deceleration from v = u + at ⇒ t = (v - u)/a
t = (v - u)/a = (0 - 13.41 ft/s)/-0.3 ft/s² = - 13.41 ft/s/-0.3 ft/s² = 44.7 s ≅ 45 s
So it takes 45 seconds to stop.
The answer to this is D. Probability levels for finding statistical significance increase as statistical power decreases. The statement concerning statistical probability is not true as this is d.
I hope this helps!
A = change in velocity / change in time
in your case a = 0(final velocity)-30(initial velocity)/10
so, a = -30/10 = -3 m/s^2
I hope this helps you!