Most chemical changes in living things cannot take place without what?

How many moles of CCI are there in 78.2 g of CCI.?

vaieri [72.5K]

Answer:

0.508 mole

Explanation:

NOTE: Since no hydrogen is attached to the compound given in question above, it means the compound is CCl₄.

The number of mole present in 78.2 g of CCl₄ can be obtained as follow:

Mass of CCl₄ = 78.2 g

Molar mass of CCl₄ = 12 + (35.5×4)

= 12 + 142

= 154 g/mol

Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 78.2 / 154

Mole of CCl₄ = 0.508 mole

Therefore, 0.508 mole is present in 78.2 g of CCl₄

6 0

2 years ago

What is the gravitational force cause<br>

Norma-Jean [14]

Answer: Gravity

Explanation: The answer is gravity: an invisible force that pulls objects toward each other. ... So, the closer objects are to each other, the stronger their gravitational pull is. Earth's gravity comes from all its mass. All its mass makes a combined gravitational pull on all the mass in your body.

5 0

3 years ago

Read 2 more answers

Be sure to answer all parts. For an aqueous solution of sodium chloride (NaCl), determine the molarity of 4.05 L of a solution t

SpyIntel [72]

Answer:

$0.824\ \text{M}$

$5.62\ \text{L}$

$20.89\ \text{mol}$

Explanation:

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl = 195 g

Volume of solution = 4.05 L

Molarity of solution is

$\dfrac{195}{4.05}\times \dfrac{1}{58.44}=0.824\ \text{M}$

The molarity of the solution is $0.824\ \text{M}$

Moles of NaCl = 4.63 mol

Volume is given by

$\dfrac{4.63}{0.824}=5.62\ \text{L}$

The volume of the solution that contains the required amount NaCl is $5.62\ \text{L}$

Volume of solution = $25.35\ \text{L}$

Moles of solution is given by

$0.824\times 25.35=20.89\ \text{mol}$

The number of moles of NaCl is $20.89\ \text{mol}$ .

6 0

3 years ago

Is the cell thoeory a law

Sunny_sXe [5.5K]

No, It's not a law.

4 0

3 years ago

Suppose 7.05 g of zinc iodide is dissolved in 150. mL of a 0.20M aqueous solution of potassium carbonate. Calculate the final mo

sasho [114]

Answer:

$M=0.294M$

Explanation:

Hello!

In this case, since the molarity of the iodide ion is computed by dividing the moles of iodide ions by the volume of solution in liters (0.150 L), we first need to compute the moles of zinc iodide (ZnI2) by using its molar mass and then using a mole ratio of 1 mol of zinc iodide to 2 mol of iodide ion:

$n_{I^-}=7.05gZnI_2*\frac{1molZnI_2}{319.22 gZnI_2}*\frac{2molI^-}{1molZnI_2}=0.0442molI^-$

Therefore, the resulting molarity turns out:

$M=\frac{0.0442molI^-}{0.150L} \\\\M=0.294M$

Best regards!

4 0

3 years ago