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Step2247 [10]
3 years ago
12

(TCO 2) A 120 VAC, 10 A electric heater needs to be connected to a 120 V, 2 A PLC output module. What will happen if the heater

is directly connected to the module
Engineering
1 answer:
aalyn [17]3 years ago
3 0

Answer:

When a 10A electric heater is directly connected to 2A PLC output module for switching then PLC output module will most probably be damaged due to excess current drawn by the electric heater.

Explanation:

Usually, the high current rating loads such as electric heater are connected to the PLC via relays or contactors. A relay or contactor is a device which is used to make or break the electrical circuit.

These relays are capable of handling heavy currents and perform reliable switching. Contactor is preferred when the current is more than 10 A and relay is preferred when current is less than or equal 10 A.

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Determine the reactor volume (assume a CSTR activated sludge aerobic reactor at steady state) required to treat 5 MGD of domesti
12345 [234]

Answer:

1.0MG

Explanation:

to solve this problem we use this formula

S₀-S/t = ksx --- (1)

the values have been given as

concentration = S₀ = 250mg

effluent concentration = S= 10mg

value of K = 0.04L/day

x = 3000 mg

when we put these values into this equation,

250-10/t = 0.04x10x3000

240/t = 1200

we cross multiply from this stage

240 = 1200t

t = 240/1200

t = 0.2

remember the question says that 5MGD is required to be treated

so the volume would be

v = 0.2x5

= 1.0 MG

4 0
3 years ago
Charging method .Constant current method​
mina [271]

Answer:

There are three common methods of charging a battery; constant voltage, constant current and a combination of constant voltage/constant current with or without a smart charging circuit.

Constant voltage allows the full current of the charger to flow into the battery until the power supply reaches its pre-set voltage.  The current will then taper down to a minimum value once that voltage level is reached.  The battery can be left connected to the charger until ready for use and will remain at that “float voltage”, trickle charging to compensate for normal battery self-discharge.

Constant current is a simple form of charging batteries, with the current level set at approximately 10% of the maximum battery rating.  Charge times are relatively long with the disadvantage that the battery may overheat if it is over-charged, leading to premature battery replacement.  This method is suitable for Ni-MH type of batteries.  The battery must be disconnected, or a timer function used once charged.

Constant voltage / constant current (CVCC) is a combination of the above two methods.  The charger limits the amount of current to a pre-set level until the battery reaches a pre-set voltage level.  The current then reduces as the battery becomes fully charged.  The lead acid battery uses the constant current constant voltage (CC/CV) charge method. A regulated current raises the terminal voltage until the upper charge voltage limit is reached, at which point the current drops due to saturation.

4 0
3 years ago
List two ways you can make an informal survey
solniwko [45]

The two ways you can use to make an informal survey are:

  • make field observations
  • interview people using informal unstructured techniques

<h3>What are informal surveys?</h3>

In informal surveys can be regarded as a type of survey that can be made by the researcher by going to the field themselves and this can be done by using different methods or ways.

For instance, the researcher can go out to interview people that can give the data that is needed about the research such as informally asking them questions,  unstructured techniques can also be used to solve critical issues.

learn more about survey at: brainly.com/question/6947486

#SPJ9

8 0
2 years ago
Read 2 more answers
• Build upon the results of problem 3-85 to determine the minimum factor of safety for fatigue based on infinite life, using the
Rudik [331]

Answer:

minimum factor of safety for fatigue is = 1.5432

Explanation:

given data

AISI 1018 steel cold drawn as table

ultimate strength Sut = 63.800 kpsi

yield strength Syt = 53.700 kpsi

modulus of elasticity E = 29.700 kpsi

we get here

\sigma a = \sqrt{(\sigma a \times kb)^2+3\times (za\times kt)^2}    ...........1

here kb and kt = 1 combined bending and torsion fatigue factor

put here value and we get

\sigma a =  \sqrt{(12 \times 1)^2+3\times (0\times 1)^2}  

\sigma a = 12 kpsi

and

\sigma m = \sqrt{(\sigma m \times kb)^2+3\times (zm\times kt)^2}     ...........2

put here value and we get

\sigma m = \sqrt{(-0.9 \times 1)^2+3\times (10\times 1)^2}  

\sigma m = 17.34 kpsi

now we apply here goodman line equation here that is

\frac{\sigma m}{Sut} +  \frac{\sigma a}{Se} = \frac{1}{FOS}     ...................3

here Se = 0.5 × Sut

Se = 0.5 × 63.800 = 31.9 kspi

put value in equation 3 we get

\frac{17.34}{63.800} +  \frac{12}{31.9} = \frac{1}{FOS}  

solve it we get

FOS = 1.5432

6 0
3 years ago
The dot plot shows the number of cupcakes bought by each person who came to a bake sale.
Maslowich

The true statement about the dot plot is 1 has 4 and 0 dots.

Explanation:

  • after creating a Bar chart 4 is the right answer.
  • The highest among st all the other plots is 1 but 4 shows 3.
  • Taking an average from all the data points 3 comes to the right answer.
  • Median the central Mid-point is 3.
  • Mode also comes to 3.
  • It is skewed on the right due to the 1st one.
  • Skewed shows the data point either increasing or in decreasing.
  • There a to Bi- histograms which has two ups and downs.
  • The true statement has to be as Mean=Median=Mode is 3.

6 0
3 years ago
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