Equation is:
Ca(NO3)2 + Na3PO4 —> NaNO3 + Ca3(PO4)2
Balance it out
3Ca(NO3)2 + 2Na3PO4 —> 6NaNO3 + Ca3(PO4)2
You have 96.1g of Calcium Nitrate
Moles = Mass/Molar Mass
Molar mass of Calcium Nitrate is 164.088 g/mol
96.1g / 164.088 g/mol =0.586 moles
Mole ratio is 3:1
Therefore 0.586/3 moles of calcium phosphate
Moles x molar mass = mass
0.586/3 x 310.18 g/mol = 60.6~g roughly as theoretical yield
Answer:
The noble gases have 8 valence electrons in their outermost electron shell. In other words, they have full out shells. These elements are highly stable.
Molality is defined as the number of moles of solute in 1 kg of solvent
the number of moles of solute - 8.1 mol
mass of solvent - 4847 g
there are 8.1 mol in 4847 g of solvent
we need to know how many moles are in 1 kg of solvent
therefore number of moles in 1 kg of solvent is - 8.1 mol / 4.847 kg
molality of solution is - 1.67 mol/kg
Answer:
0.21 kg
Step-by-step explanation:
Volume of cola = 2.0 L × (33.8 fl oz/1L)
= 67.6 fl oz
Grams of sugar = 67.6 fl oz × (25 g sugar/8.0 fl oz)
= 210 g sugar
Kilograms of sugar = 210 g × (1 kg/1000 g)
= 0.21 kg
Answer:
1034 yrs
Explanation:
The equation to use in this question is:
t = -2.303/k log (A/A₀) where
A= present number of disintegrations
A₀ = intial number of disintegrations
k = decay constant
The decay constant we will obtain it from the given hal-life:
k: 0.693/t₁/₂, t₁/₂ = half-life ⇒
k: 0.693 / 5730 y = 1.209 x 10⁻⁴ /y⁻¹
t = - 2.303 / 1.209 x 10⁻⁴ /y⁻¹ x log (13.1/15.3) = 1034 yrs
