Answer:
<h2>
Work done by the gas is given as</h2><h2>
</h2>
Explanation:
As we know that the process is isothermal so here work done is given as
here we know that
now we have
so we have
Answer:
559.5 N
Explanation:
Applying,
v² = u²+2gs............. Equation 1
Where v = final velocity,
From the question,
Given: s = 5.10 m, u = 0 m/s ( from rest)
Constant: 9.8 m/s²
Therefore,
v² = 0²+2×9.8×5.1
v² = 99.96
v = √(99.96)
v = 9.99 m/s
As the diver eneters the water,
u = 9.99 m/s, v = 0 m/s
Given: t = 1.34 s
Apply
a = (v-u)/t
a = 9.99/1.34
a = -7.46 m/s²
F = ma.............. Equation 2
Where F = force, m = mass
Given: m = 75 kg, a = -7.46 m/s²,
F = 75(-7.46)
F = -559.5 N
Hence the average force exerted on the diver is 559.5 N
Answer:
36.9 m/s
Explanation:
From;
v^2 = u^2 + 2as
Where;
v = final velocity =?
a = acceleration = 3.4 m/s^2
u = initial velocity = 0 m/s
s = distance covered = 200 meters
v^2 = 0^2 + 2 * 3.4 * 200
v^2 = 1360
v = √1360
v = 36.9 m/s
A rock is dropped from a 100-m-high cliff. How long do the first 50 meters and the second 50 meters take to fall?
(a) The first 50 meters:
h1 = 0.5 x a x t12
50 m = 0.5% x 9.8% x t12
t1 = 3.19 s
50 meter fall time equals 3.19 seconds.
(a) Counting all 100 meters:
h2 = 0.5 x a x t22
100 m = 0.5% x 9.8% x t22
t2 = 4.52 s
Time to fall 50 meters is equal to t2 - t1 = 1.33 s.
<h3>What is meter?</h3>
The Earth's circumference is around 40000 km, according to the original definition of the metre in 1793, which was one ten-millionth of the distance between the equator and the North Pole on a great circle. The metre was redefined in 1799 using a model metre bar (the actual bar used was changed in 1889). The definition of the metre in terms of a certain number of wavelengths of a specific krypton-86 emission line was made in 1960.
To know more about meter, visit;
brainly.com/question/14475998
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