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andreev551 [17]
4 years ago
10

List two things (number them 1 and 2) that are special about hydrogen allowing it to form hydrogen bonds when bound to oxygen: 1

. ....... 2. ....... List two things (number them 3 and 4) that are special about oxygen allowing it to form hydrogen bonds when bound to hydrogen: 3. ...... 4. ......
Chemistry
2 answers:
Temka [501]4 years ago
6 0

Answer:

1. Presence of one valence electron in the outermost shell.

2. Less electronegative than Oxygen.

3. Six valence electrons its outer shell. So it needs to 2 electrons to get stable octet.

4. It is highly electronegative.

Explanation:

Hydrogen with the electronic configuration of 1s^1 needs 1 electron in its outer shell to be stable while oxygen with the electronic configuration of 1s^2 2s^2 2p^4 needs 2 electrons to complete octet state.

2 hydrogen atoms therefore bond covalently (sharing of electrons) with 1 Oxygen atom via hydrogen bond to form a water molecule.

This covalent hydrogen bond formed is polar as oxygen will attract electrons towards it due to high electronegativity.

Gemiola [76]4 years ago
3 0

Answer:

Hydrogen

1. has one electron in the outermost shell

2.It is less electronegative

Oxygen

3.It requires two electrons to complete its outer shell

4.It is more electronegative

Explanation:

Each hyrogen of two will share its electron with oxygen.Oxygen requires two electrons to complete its outer shell so it will  share with two hydrogen. Covalent bonds formed will be polar as oxygen will attract electrons towards it due to high electronegativity. This happens in water molecule

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H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).
timofeeve [1]

Answer:

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Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

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Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

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4 0
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Please see the attachments below

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