To solve this problem we will apply the concepts related to equilibrium, for this specific case, through the sum of torques.
![\sum \tau = F*d](https://tex.z-dn.net/?f=%5Csum%20%5Ctau%20%3D%20F%2Ad)
If the distance in which the 600lb are applied is 6in, we will have to add the unknown Force sum, at a distance of 27in - 6in will be equivalent to that required to move the object. So,
![F*(27-6)= 6*600](https://tex.z-dn.net/?f=F%2A%2827-6%29%3D%206%2A600)
![F = \frac{6*600}{21}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B6%2A600%7D%7B21%7D)
![F= 171.42 lb](https://tex.z-dn.net/?f=F%3D%20171.42%20lb)
So, Force that must be applied at the long end in order to lift a 600lb object to the short end is 171.42lb
When a force causes a body to move, work is done on the object by the force. Work is the measure of the energy transfer when a force 'F' moves an object through a distance 'd'. So we say that energy is transferred from one energy store to another when work is done, and therefore, energy transferred = work done.
Answer:
The direction of electric field and equipotential line at the same point are always PERPENDICULAR TO THE ELECTRIC FIELD.
Explanation:
Equipotential surface is a three dimensional part of equipotential lines.
Equipotential lines are a type of contour lines that is use to trace lines that have the same altitude on the map and the altitude is the electric potential.
Equipotential lines are always perpendicular to electric potential because the lines creates three dimension equipotential surface.
Noble gasses have an outer shell full of electrons. A full outer energy level is the most stable arrangement of electrons. As a result, noble gases cannot become more stable by reacting with other elements and gaining or losing valence electrons. Therefore, noble gases are rarely involved in chemical reactions and almost never form compounds with other elements.