Ca=40
C=12
O=16
1 mole of CaCO3 has 100 grams
So 50 grams is 0.5 mole
Answer:
Partial pressure O₂ = 1.78 atm
Explanation:
We can apply the mole fraction to solve the question:
Moles of gas / Total moles = Partial pressure of gas / Total pressure
Total moles = 1 H₂ + 2.5 He + 2O₂ = 4.5 moles
2 mol O₂ / 4.5 mol = Partial pressure O₂ / 4 atm
(2 mol O₂ / 4.5 mol ) . 4 atm = Partial pressure O₂ → 1.78 atm
The answer is C) Temperature
