Answer:
Explanation:
I can do it, but it may not be right. The atoms/ions and charges are all balanced, but I'm just not sure.
12Br2 + 12H20 ==> 4BrO3^- +20Br- + 24H+ You can divide this by 4
3Br2 + 3H20 ==> BrO3^- + 5Br^- + 6H+
Element/ion Left Right
Br 3*2 = 6 1 + 5 = 6
H 6 6H+
O 3 3
Charges 0 -1 - 5 + 6 = 0
The H+ represents an Acid. The problem is it says that the reaction takes place in an acid. It is so long ago, I don't remember if this includes being on the right.
Anyway it is balanced.
The bond polarities of SiH₄ are polar. The molecular shape is tetrahedral. The molecule is nonpolar.
<h3>Explanation</h3>
As seen on the diagram, there are four Si-H bonds in a molecule of SiH₄. Electronegativity values:
The two atoms differ in electronegativity. As a result, the Si-H bond is polar.
There are four valence electrons in one Si atom. Each of the four electron will go to a Si-H bond. The Si atom in SiH₄ will have no lone pairs. The four Si-H bonds count towards four electron domains. As a result, the SiH₄ atom is tetrahedral.
Dipoles from each Si-H bond are equal. They are poised in a tetrahedral shape. As a result, their dipole balance each other. Overall, SiH₄ molecule will have no net dipole.
1ft=.3048meter
So if we have 2063ft and want it in meters we just do a simple unit conversion.
(2063ft)(.3048meters/1ft)=628.8meters. Here ft cancel out and leave us with meter units.
Any questions please feel free to ask. Thank you.
Answer:
you could've googled it but here.
Explanation:
The former OSHA limit for sodium hydroxide (also known as caustic soda or Iye) was 2 mg/m3 as an 8-hour TWA. OSHA proposed a 2-mg/m3 ceiling limit for sodium hydroxide, based on the ACGIH- and NIOSH-recommended limits.
From the combustion of octane, the formaldehyde will be formed as this equation:
C8H18 + O2 → CH2O + H2O this is the original equation but it is not a balanced equation, so let's start to balance it:
the equation to be balanced so the number of atoms on the right side of the equation sholud be equal with the number of atoms on the lef side.
-we have 8 C atoms on left side and 1 atom on the right side so we will try putting 8 CH2O on the right side instead of CH2O
C8H18 + O2 → 8 CH2O + H2O
we have 2 O atoms on the left side and 9 atoms on the right side so we will try first to put 9 O2 instead of O2 on the left side and put 2H2O on the right side and put 16 CH2O instead of 8 CH2O to make the atoms of O are equal on both sides = 18 atoms
C8H18 + 9 O2 → 16 CH2O + 2H2O
put now we have 8 atom C on the left side and 16 atom on the right side so, we will put 2 C8H18 instead of C8H18 now we get this equation:
2C8H18 + 9O2 →16 CH2O + 2H2O
-now we have 36 of H atoms on both sides.
- and 16 of C atoms on both sides.
- and 18 of O atoms on both sides.
now all the number of atoms of O & C & H are equal on both sides
∴ 2C8H18 + 9O2 → 16 CH2O + 2 H2O
is the final balanced equation for the formation of formaldehayde
