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Lana71 [14]
3 years ago
5

Technician A says that some multiplexing systems use a data bus that consist of a twisted pair of wires. Technician B says that

some multiplexing systems use a data bus that consists of a single wire. Who is correct?
Engineering
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer: Both Technician A and Technician B are correct.

Explanation:

Multiplexing system makes communication within several separate modules possible via the use of one (or two wires). In this case, the data bus has a single wire. Therefore, Technician B is correct.

Also, the data backbone of a multiplex system which is called a twisted wire pair chapter consist of twisted pair of wires which are thus twisted in order to reduce the susceptibility of EMI. So Technician B is also correct.

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A mass of 12 kg saturated refrigerant-134a vapor is contained in a piston-cylinder device at 240 kPa. Now 300 kJ of heat is tran
Ket [755]

Answer:

I = 12.706 Amps

Explanation:

Given:

- The mass of saturated R-134a m = 12 kg

- The initial Conditions

      P_1 = 240 KPa

      Saturated Vapor

- The final Conditions

      P_2 = 240 KPa

      T_2 = 70° C

- The amount of Heat transferred Q_in = 300 KJ

- The voltage of current source V = 110 V

- The current supplied by the source = I

- The time duration Δt = 6 min

Find:

Determine the current supplied I.

Solution:

- Look-up enthalpies h_1 and h_2 at both states using Tables A-11 and A-13.

       P_1 = 240 KPa    

       Saturated Vapor ----------> h_1 = h_g = 247.32 KJ/kg

       P_2 = 240 KPa

       T_2 = 70° C        ----------> h_2 = 314.53 KJ/kg

- Using First Thermodynamic Law, set up an energy balance:

                           E_in - E_out = ΔE_system

                           Q_in + W_electric,in - W_out = Δ U

                           Q_in + V*I*Δt - W_out = Δ U

                           Q_in + V*I*Δt = Δ H

                           Q_in + V*I*Δt = m*( h_2 - h_1 )

- Make the current I the subject of the expression above:

                            V*I*Δt = m*( h_2 - h_1 ) - Q_in

                            I = [ m*( h_2 - h_1 ) - Q_in ] / V*Δt

- Plug in the values in the expression derived above and evaluate current of source I:

                            I = [ 12*( 314.53 - 247.32 ) - 300 ]*1000 / 110*6*60

                            I = 12.706 Amps                              

- The required source of current is I = 12.706 Amps.

4 0
3 years ago
The heat transfer rate due to free convection from a vertical surface, 1 m high and 0.6 m wide, to quiescent air that is 20 K co
andreyandreev [35.5K]

Answer:

The ratio of heat transfer rate is 0.88

Explanation:

Given;

Case1 :

height of vertical surface, L = 1 m

width of vertical surface, w = 0.6 m

Case 2:

height of vertical surface, L = 0.6 m

width of vertical surface, w = 1 m

At an assumed film temperature of air = 300 K

then, read off from heat transfer table, temperature inverse β, surface area flow rate v, and Pr, to determine Rayleigh number for the two cases.

β = 1/300 = 0.00333 K⁻¹

v = 15.89 x 10⁻⁶ m²/s

Pr = 0.69

Case 1, L = 1 m

R_a = \frac{g\beta TL^3P_r}{v^2}

R_a = \frac{9.8*0.00333* 20*1^3*0.69}{(15.89x10^{-6})2} \\\\R_a = 1.784 *10^9

Case 2, L = 0.6 m

R_a = \frac{g\beta TL^3P_r}{v^2} \\\\R_a = \frac{9.8*0.00333* 20*0.6^3*0.69}{(15.89*10^{-6})^2}\\\\ R_a = 3.853 *10^8

From the values of Rayleigh numbers above, case 1 is Turbulent flow while case 2 is laminar flow

Thus: C₁ = 0.1, n₁ = ¹/₃

          C₂ = 0.59, n₂ = 1/4

Ratio of heat transfer rate is given as:

\frac{q_1}{q_2} = \frac{h_1 \delta T}{h_2 \delta T} \\\\\frac{q_1}{q_2} = \frac{h_1}{h_2} \\\\But, \frac{hL}{k} = CR_a^n L, \ \ h=\frac{k}{L}(CR_a^n L)\\\\\frac{q_1}{q_2} = \frac{C_1R_a_1^n L_2}{C_2R_a_2^n L_1} = \frac{0.1(1.784*10^9)^{\frac{1}{3}} *0.6}{0.59(3.853*10^8)^{\frac{1}{4}} *1} \\\\\frac{q_1}{q_2} = \frac{72.76}{82.66} = 0.88

Therefore, the ratio of heat transfer rate is 0.88

4 0
3 years ago
Give the general layout of centrifugal pump.​
Nadusha1986 [10]

Answer:

A centrifugal pump is a rotating machine that pumps liquid by forcing it through a paddle wheel or propeller called an impeller. It is a most common type of industrial pump. By the effect of the rotation of the impeller, the pumped fluid is drawn axially into the pump, then accelerated radially, and finally discharged tangentially.

Explanation:

Suppliers generally offer charts in the plan, which present the various things at the nominal operating point using two main arrangements: the inductors and the balancing pants.

7 0
4 years ago
Many companies are combining their online business activities with an existing physical presence. In about 100 words, explain wh
Daniel [21]

Answer:

Companies are combining their online business activities with their existing physical presence in order to lower costs of their operations. When both these things are combined labor costs are reduced because with online presence the company has to have limited number of branches, inventory costs are reduced because additional inventories for every physical outlet is not required and delivery costs are reduced because now company don't have to supply the things to all the outlets on regular basis.

Trust of the people is also improved because mostly people are reluctant to order from the brands that only have their online store and donot have any physical presence. Value added services are provided by a company who have both online and offline presence like home delivery and customized offerings.

 

3 0
3 years ago
The enthalpy of the water entering an actual pump is 500 kJ/kg and the enthalpy of the water leaving it is 550 kJ/kg. The pump h
n200080 [17]

Answer:500,551.02

Explanation:

Given

Initial enthaly of pump \left ( h_1\right )=500KJ/kg

Final  enthaly of pump \left ( h_2\right )=550KJ/kg

Final  enthaly of pump when efficiency is 100%=h_2^{'}

Now pump efficiency is 98%

\eta=\frac{h_2-h_1}{h_2^{'}-h_1}

0.98=\frac{550-500}{h_2-500}

h_2=551.02KJ/kg

therefore initial and final enthalpy of pump for 100 % efficiency

initial=500KJ/kg

Final=551.02KJ/kg

3 0
3 years ago
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