<span>0.298 M
The balanced equation for the reaction is
HCl + NaOH = H2O + NaCl
So for every mole of NaOH used, one mole of HCl is neutralized. So let's determine how many moles of NaOH we used. That will simply be the volume (in liters) of solution multiplied by the molarity. So
0.0493 L * 0.151 mol/L = 0.0074443 mol
Because of that 1:1 ratio, we now know that 0.0074443 moles of HCl was in the sample. Since molarity is moles per liter, a little division will give us the molarity of the HCl solution. So
0.0074443 mol / 0.025 L = 0.297772 mol/M = 0.297772 M
Rounding to 3 significant figures gives 0.298 M.</span>
The first statement is False... as
For exothermic reaction :
A+B》 C+D + HEAT..(heat is considered as a product)... as for endo.. heat is a reactant.
So tjey can't be of the same energy...
2nd one...based on the
A+B》 C+D+HEAT...For exo reaction... the product have more Heat energy than potential...so its false
Recall...energy can nither be created nor destroyed but converted from one form to another....
The 4th one however is true for heat...the reactants have nore energy than the products..
A+B+HEAT》C+D
I believe the balanced chemical equation is:
C6H12O6 (aq) + 6O2(g)
------> 6CO2(g) + 6H2O(l)
First calculate the
moles of CO2 produced:
moles CO2 = 25.5 g
C6H12O6 * (1 mol C6H12O6 / 180.15 g) * (6 mol CO2 / 1 mol C6H12O6)
moles CO2 = 0.8493 mol
Using PV = nRT from
the ideal gas law:
<span>V = nRT / P</span>
V = 0.8493 mol *
0.08205746 L atm / mol K * (37 + 273.15 K) / 0.970 atm
<span>V = 22.28 L</span>
<span>Answer:
Yes, the n for potassium would be 4, and for neon would be 2.
Just count which row of the periodic table you are on.
The "L" tells you whether the highest-energy electron is in
an "s" orbital (L=0) or a "p" orbital (L=1) or a "d" orbital (L=2) or an "f" orbital (L=3).
The manner in which these orbitals are filled is:
for each of the first three rows (up to argon),
two electrons in the "s" orbital are filled first, then 6 electrons in the "p"orbitals.
The potassium row also starts with filling the "s" orbital at the new "n" level (4)
but then goes back to filling up the "d" orbitals of n=3 before it fills up the "p"s for n=4.
OK, so potassium has n=4, L = 0, while neon has n=2, L = 1.
The quantum numbers connected with "an element" are always referring to the
highest-energy electron, i.e., the one that was absent in the predecessor element
of the periodic table. When you go from potassium to calcium,
you still get n=4, L = 0, because there are two positions in the "s" orbital.
But when you go from calcium to scandium, suddenly you go back to n=3, L = 2 ("d" orbital).</span>
