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yarga [219]
3 years ago
13

Explain why it takes more energy to remove the second electron from a lithium atom than it does to remove the fourth electron fr

om a carbon atom.
Physics
2 answers:
slava [35]3 years ago
8 0
It takes more energy to remove the second electron from a lithium atom than it does to remove the fourth electron from a carbon atom because its inner core e, not valence e. C's 4th removed e is still a valence e. And also <span>because more nuclear charge acting on the second electron, it is more close to the nucleus, thus the the protons attract it more than the 4th electron.</span>
Orlov [11]3 years ago
8 0

The energy required to remove second electron from lithium is more as compared to removing fourth electron from carbon

EXPLANATION:

The amount of energy required to remove an electron from an isolated atom is called as ionization energy of the electron.

The second ionization energy of lithium atom is more as compared to fourth ionization energy of carbon atom. It is so because the second electron which is to be emitted from the K-shell of lithium atom, is tightly bound by the nucleus as the orbit is very closer to the nucleus.

In case of carbon, the fourth electron is present in the valence shell.The radius of valence shell is not so close as compared to lithium.The screening effect is also more for carbon as compared to lithium.

Hence, the energy required to remove a second electron from lithium is more that the energy required to remove fourth electron from carbon.



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4. For a series of experimentally measured values give the definition of (a) average or mean value (b) the deviation from the me
Naya [18.7K]

Answer:

a)   x_average = ∑ x_{i} / n , b) Δx_{i} = x_{i} –x_average,

d) σ = √(1/n-1  ∑ Dx_{i}² )

Explanation:

Some definitions are requested

a) the average value is the sum of all the values ​​divided by the number of them, if the uncertainties are random, this is the closest value to the real one

       x_average = ∑ x_{i} / n

b) The deviation from the mean value or absolute error is the measured value minus the average value

       Δx_{i} = x_{i} –x_average

c) is the average value of the deviations

        Δx_average = ∑ Δx_{i} / n

d) It is a measure of the dispersion of the values ​​with respect to their average value, it takes the worst of all cases, widely used for large numbers of data

          σ = √(1/n-1  ∑ Dx_{i}² )

Experimental results should be given as follows

  Average value ± uncertainty and the standard deviation

  (x_average + - Δx_average)

  σ

3 0
3 years ago
A spring stretches 0.150 m when a 0.30 kg mass is hung from it. The spring is then stretched an additional 0.100 m from this equ
DochEvi [55]

Answer:

a)  k=19.6N/m

b)  V_m=0.81m/s

c)  a_m=6.561m/s^2

d)  K.E=0.096J

e)  T=0.78sec &F=1.29sec

f)   mx'' + kx' =0

Explanation:

From the question we are told that:

Stretch Length L=0.150m

Mass m=0.30kg

Total stretch lengthL_t=0.150+0.100=>0.25

a)

Generally the equation for Force F on the spring is mathematically given by

F=-km\\\\k=F/m\\\\k=\frac{m*g}{x}\\\\k=\frac{0.30*9.8}{0.15}

k=19.6N/m

b)Generally the equation for Max Velocity of Mass on the spring is mathematically given by

V_m=A\omega

Where

A=Amplitude

A=0.100m

And

\omega=angulat Velocity\\\\\omega=\sqrt{\frac{k}{m}}\\\\\omega=\sqrt{\frac{19.6}{0.3}}\\\\\omega=8.1rad/s

Therefore

V_m=A\omega\\\\V_m=8.1*0.1

V_m=0.81m/s

c)

Generally the equation for Max Acceleration of Mass on the spring is mathematically given by

a_m=\omega^2A

a_m=8.1^2*0.1

a_m=6.561m/s^2

d)

Generally the equation for Total mechanical energy of Mass on the spring is mathematically given by

K.E=\frac{1}{2}mv^2

K.E=\frac{1}{2}*0.3*0.8^2

K.E=0.096J

e)

Generally the equation for  the period T is mathematically given by

\omega=\frac{2\pi}{T}

T=\frac{2*3.142}{8.1}

T=0.78sec

Generally the equation for  the Frequency is mathematically given by

F=\frac{1}{T}

F=1.29sec

f)

Generally the Equation of time-dependent vertical position of the mass is mathematically given by

mx'' + kx' =0

Where

'= signify order of differentiation

7 0
3 years ago
Physical values in the real world have two components: magnitude and
Nadusha1986 [10]

Answer:

Dimension.

Explanation:

6 0
3 years ago
A less massive moving object has an elastic collision with a more massive object that is not moving. Compare the initial velocit
stepladder [879]

Assume that the small-massed particle is m and the heavier mass particle is M.

Now, by momentum conservation and energy conservation:

   mv = mv_{m} + Mv_{M}

   mv^{2} = mv^{2}_{m} + Mv^{2}_{M}

Now, there are 2 solutions but, one of them is useless to this question's main point so I excluded that point. Ask me in the comments if you want the excluded solution too.

   v_{m} = v\frac{m - M}{m + M}\\\\\\v_{M} = v\frac{m + M}{m + M}\\

So now, we see that v_{m} < 0 and v_{M} > 0. So therefore, the smaller mass recoils out.

Hope this helps you!

Bye!

7 0
3 years ago
Select the correct answer. Which of Newton's laws explains why your hands get red when you press them hard against a wall? A. Ne
STatiana [176]

Answer:

D newton third law

Explanation:

good luck

8 0
2 years ago
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