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yarga [219]
3 years ago
13

Explain why it takes more energy to remove the second electron from a lithium atom than it does to remove the fourth electron fr

om a carbon atom.
Physics
2 answers:
slava [35]3 years ago
8 0
It takes more energy to remove the second electron from a lithium atom than it does to remove the fourth electron from a carbon atom because its inner core e, not valence e. C's 4th removed e is still a valence e. And also <span>because more nuclear charge acting on the second electron, it is more close to the nucleus, thus the the protons attract it more than the 4th electron.</span>
Orlov [11]3 years ago
8 0

The energy required to remove second electron from lithium is more as compared to removing fourth electron from carbon

EXPLANATION:

The amount of energy required to remove an electron from an isolated atom is called as ionization energy of the electron.

The second ionization energy of lithium atom is more as compared to fourth ionization energy of carbon atom. It is so because the second electron which is to be emitted from the K-shell of lithium atom, is tightly bound by the nucleus as the orbit is very closer to the nucleus.

In case of carbon, the fourth electron is present in the valence shell.The radius of valence shell is not so close as compared to lithium.The screening effect is also more for carbon as compared to lithium.

Hence, the energy required to remove a second electron from lithium is more that the energy required to remove fourth electron from carbon.



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A person pushes on the handle of a lawnmower with a force of 280. n. if the handle makes an angle of 40.0 degrees with the groun
Serggg [28]
<span>Force F = 280 N Angle with the ground = 40 degrees Weight of the Lawnmower = 350 N Velocity is constant so Acceleration is 0 So Forward force Ff = F cos theta = 280 cos40 Frictional force with resists to back Fb = (u x Force from pressure) + vertical component of Force, where u is the coefficient of friction. Fb = (u x m x g) + (u x 280sin40) AS Ff = Fb => 280 cos40 = u x ((m x g) + 280sin40) u = 280 cos40 / ((350 x 9.81) + 280sin40) = 214.49 / () = 0.405 So the coefficient of friction u = 0.405</span>
8 0
3 years ago
Read 2 more answers
A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m
Degger [83]

Answer:

a)t  = 1,43 s

b) V = 10,49 m/s

c) V₀ₓ = 10,49 m/s   ;    V₀y = 14,01 m/s

d) Vf = 17,5 m/s

Explanation:

According to the problem statement

V₀ = V₀ₓ    and  V₀y = 0

And at the end of the movement t = ?  the distance y = 10 m

Therefore as

h = V₀y - (1/2)*g*t²

Vertical distance y = h = 10 = V₀y*t - 0,5 (-9,8)*t²

10 = 4,9*t²

t² = 10/4,9    ⇒  t² = 2,04 s

t  = 1,43 s

a) 1,43 s is the time of movement

b) V₀ = V₀ₓ        V₀y = 0     and  V₀ₓ = Vₓ     ( constant )

Just before touching the ground, the horizontal distance is

hd = 15 = Vₓ * t

Then  15 /1,43 = Vₓ = V₀ₓ

Vₓ = 10,49 m/s

Then initial speed is V = 10,49 m/s    since V₀y = 0

Vf² = Vₓ² + Vy²

Vyf = V₀y - g*t

Vyf =  0 - 9,8 *1,43

Vyf = - 14,01 m/s

And finally the speed when the projectile strike the ground is:

Vf² = Vₓ² + Vy²

Vf = √ (10,49)² + (14,01)²

Vf = 17,50 m/s

3 0
4 years ago
You and a friend each apply 500 N of force to move a cement block 50 cm. How much work was done on the cement block?
Rama09 [41]

Answer:

 W = 500 J

Explanation:

Work is defined by

         W = F . x

if we develop the dot product

         W = F x cos θ

where is the angle between the force and the displacement, in this case the angle is zero, so cos 0 = 1

          W = F x

indicate that each person applies a force of 500 N, so the total force is

         F = 1000 N

let's reduce the distance to the SI system

          x = 50 cm = 0.50 m

let's calculate

          W = 1000 0.50

          W = 500 J

3 0
3 years ago
PLEASE HELP a current of 0.5 A flows with a resistance of 50 ohms what is the e.m.f applied NEED HELP ASAP AND BRAINLIEST​
Vanyuwa [196]

Answer:

25 volts

Explanation:

voltage = current × resistance

v = i \times r \\ v = 0.5 \times 50 \\ v = 25v

6 0
2 years ago
Which is measured by the power of a machine?
Alina [70]

the rate of work done or doing work is usually measured by the power of a machine .

7 0
3 years ago
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