something that is figurative place where a person locates the source of responsibility in his or her life.

2. A 20 cm object is placed 10cm in front of a convex lens of focal length 5cm. Calculate

adoni [48]

Answer:

 » Image distance :

${ \tt{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }} \\$

v is image distance
u is object distance, u is 10 cm
f is focal length, f is 5 cm

${ \tt{ \frac{1}{v} + \frac{1}{10} = \frac{1}{5} }} \\ \\ { \tt{ \frac{1}{v} = \frac{1}{10} }} \\ \\ { \tt{v = 10}} \\ \\ { \underline{ \underline{ \pmb{ \red{ \: image \: distance \: is \: 10 \: cm \: \: }}}}}$

 » Magnification :

• Let's derive this formula from the lens formula:

${ \tt{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }} \\$

» Multiply throughout by fv

${ \tt{fv( \frac{1}{v} + \frac{1}{u} ) = fv( \frac{1}{f} )}} \\ \\ { \tt{ \frac{fv}{v} + \frac{fv}{u} = \frac{fv}{f} }} \\ \\ { \tt{f + f( \frac{v}{u} ) = v}}$

• But we know that, v/u is M

${ \tt{f + fM = v}} \\ { \tt{f(1 +M) = v }} \\ { \tt{1 +M = \frac{v}{f} }} \\ \\ { \boxed{ \mathfrak{formular : } \: { \tt{ M = \frac{v}{f} - 1 }}}}$

v is image distance, v is 10 cm
f is focal length, f is 5 cm
M is magnification.

${ \tt{M = \frac{10}{5} - 1 }} \\ \\ { \tt{M = 5 - 1}} \\ \\ { \underline{ \underline{ \pmb{ \red{ \: magnification \: is \: 4}}}}}$

 » Nature of Image :

Image is magnified
Image is erect or upright
Image is inverted
Image distance is identical to object distance.

4 0

2 years ago

Can sb try and do this I’m a mother trying to do school again❤️

Reika [66]

Answer:

dont do it to me i wont do it to you :)

Explanation:

5 0

3 years ago

A man steps off a diving platform lands in the water below. If he were to miss the water and land on the concrete, his change in

kari74 [83]

Answer:

if he were to land on concrete, he would most likely die and stop all momentum and for the water, he'd most likely live/die (mostly live) and slow momentum to a stop and rise up to the surface

Explanation:

that's the explanation now i gotta execute order 66

7 0

3 years ago

1.A particle is moving up an inclined plane. Its velocity changes from 15m/s to 10m/s in two seconds. What is its acceleration?

FrozenT [24]

$\huge{ \underline{ \boxed{ \bf{ \blue{Solution:}}}}}$

<h3>Provided:-</h3>

Initial velocity = 15 m/s
Final velocity = 10 m/s
Time taken = 2 s

Accleration of the particle....?

<h3>How to solve?</h3>

We will solve the above Question by using equations of motion that are:-

v = u + at
s = ut + 1/2 at²
v² = u² + 2as

Here,

v = Final velocity
u = Initial velocity
a = acceleration
t = time taken
s = distance travelled

By using first equation of motion,

⇛ v = u + at

⇛ 10 = 15 + a(2)

⇛ -5 = 2a

Flipping it,

⇛ 2a = -5

⇛ a = -2.5 m/s² [ANSWER]

❍ Acclearation is negative because final velocity is less than Initial velocity.

━━━━━━━━━━━━━━━━━━━━

5 0

4 years ago

What type of energy results in a flow of electrons?

Genrish500 [490]

Electrical energy, a form of kinetic energy results in a flow of electrons.

Explanation: 

Any kind of energy related to flow or motion of objects or particles falls under the category of kinetic energy. When an object undergoes motion or flow, it will exhibit velocity leading to kinetic energy, or energy utilized from the force applied for the motion.

In this case, the electrons will flow between the molecules due to the electric current supplied to it leading to the electrical energy, the flow of electrons generate current in opposing direction to the flow of electrons. Thus, current can be produced due to the flow of electrons on applying electrical energy.

4 0

4 years ago