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pogonyaev
3 years ago
10

How would I explain part a?

Physics
1 answer:
grandymaker [24]3 years ago
3 0

Electric field on the axis of ring on both sides is along the axial line

This electric field is away from the center on both sides

Now when an electron is placed on the axis of the ring then we will see that it will experience the electrostatic force on the electron.

The direction of force is always towards the center of the ring because here electron is a negatively charged particle and it will move opposite to the direction of electric field.

So as we release the electron from a distance of 30 cm the electron will move towards the center of ring and accelerate to its maximum speed till it will reach to the center of the ring

After that the electron will reach to the center of the ring and then moves out on the opposite side and then decelerate to zero speed as it will reach on other side.

Now after this it will again move towards the center of the ring and continue its motion similar way

So this is an oscillating motion about the center of the ring.

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Is walking just a constant state of falling?
atroni [7]

Answer:

Yes. Walking is controlled falling because you need to let go in order to move forward. If you never let your foot fall, your movements would be stilted and robotic. And according to medical engineers," When we walk normally we are constantly correcting tiny falls to keep ourselves stable."

Explanation:

8 0
3 years ago
I need someone to give me 2 answers,
yanalaym [24]
Uh.. what's the question..?
8 0
3 years ago
The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.420 with the floor. If
bonufazy [111]

Answer:

The distance is  s=  30.3 \ m

Explanation:

From the question we are told that

   The  coefficient of static friction is  \mu_s  =  0.42

    The  initial speed of the train is  u =  57 \  km /hr = 15.8 \ m/s

   

For the crate not to slide the friction force must be equal to the force acting on the train i.e

       -F_f  =  F

The negative sign shows that the two forces are acting in opposite direction

=>   mg  *  \mu_s  =  ma

=>   -g  *  \mu_s  = a

=>   a =  -9.8 *  0.420

=>   a =  -4.116 m/s^2

From equation of motion

  v^2  = u^2  +  2as

Here  v =  0 m/s since it came to a stop

=>   s=  \frac{v^2 - u^2 }{ 2 a}

 =>   s=  \frac{0 -(15.8)^2 }{ - 2 * 4.116}

=>     s=  30.3 \ m

7 0
3 years ago
Based on the data table,which car won the race?
kobusy [5.1K]

Answer:

car one

Explanation:

3 0
2 years ago
A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point
seropon [69]

since centripetal acceleration is always towards the center of the circle

so at the given position where speed and acceleration is given the center coordinate will be towards the center of circle

also we know that

a_c = \frac{v^2}{r}

11.6 = \frac{2.5^2}{R}

R = 0.54 m

so the coordinates of the center will be

(x, y) = (3.20 , (3.5 + 0.54))

(x, y) = (3.20, 4.04)

so the coordinate is (3.20 m, 4.04 m)

6 0
3 years ago
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