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3 years ago

Laminar flow, where water moves in approximately straight-line paths, characterizes ________.

Physics

1 answer:

densk [106]3 years ago

6 0

Answer:

b. slow-moving streams.

Explanation:

In Fluid Mechanics, the Reynolds numbers indicates the existence of turbulence in fluid streams. Low Reynolds numbers are related with laminar flow. The Reynolds formula is:

$Re = \frac{\rho_{water} \cdot L_{c}}{\mu_{water}} \cdot v$

The Reynolds number is directly proportional to fluid speed. Hence, slow-moving streams are a sound example of laminar flow. The correct answer is B.

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A girl is floating in a freshwater lake with her head just above the water. If she weighs 610 N, what is the volume of the subme

Elden [556K]

Answer:

The volume of the submerged part of her body is $0.0622m^{3}$

Explanation:

Let's define the buoyant force acting on a submerged object.

In a submerged object acts a buoyant force which can be calculated as :

$B=$ ρ.V.g

Where ''B'' is the buoyant force

Where ''ρ'' is the density of the fluid

Where ''V'' is the submerged volume of the object

Where ''g'' is the acceleration due to gravity

Because the girl is floating we can state that the weight of the girl is equal to the buoyant force.

We can write :

$W_{girl}=B$ (I)

Where ''W'' is weight

⇒ If we consider ρ = $1000\frac{kg}{m^{3}}$ (water density) and $g=9.81\frac{m}{s^{2}}$ and replacing this values in the equation (I) ⇒

$B=W_{girl}$

$B=610N$

ρ.V.g = 610N

$1000\frac{kg}{m^{3}}.V.(9.81\frac{m}{s^{2}})=610N$ (II)

The force unit ''N'' (Newton) is defined as

$N=kg.\frac{m}{s^{2}}$

Using this in the equation (II) :

$(9810\frac{N}{m^{3}}).V =610N$

$V=\frac{610N}{9810\frac{N}{m^{3}}}$

$V=0.0622m^{3}$

We find that the volume of the submerged part of her body is $0.0622m^{3}$

8 0

3 years ago

Will the rocket go up or will it stay on the ground ? Explain the answer if you can also please and thank you.

Goryan [66]

Answer:

the rocket will go up

Explanation:

there is less force pulling down on the rocket.

100N > 75N

5 0

3 years ago

A nuclear fission power plant has an actual efficiency of 32%. If 0.18 MW of power are produced by the nuclear fission, how much

7nadin3 [17]

Answer:

P₀ = 5.76 x 10⁻² MW

Explanation:

given,

efficiency of the power plant = 32%

Power produced by the nuclear fission = 0.18 MW

the power plant output = ?

using formula of efficiency

$\eta = \dfrac{P_0}{P}$

where P is the power produced in the power plant

P₀ is the power output of the power plant

$\eta = \dfrac{P_0}{P}$

$0.32 = \dfrac{P_0}{0.18}$

P₀ = 0.18 x 0.32

P₀ = 0.0576 MW

P₀ = 5.76 x 10⁻² MW

Power plant output is equal to P₀ = 5.76 x 10⁻² MW

8 0

3 years ago

A Student walks 2 km in 30 minutes

KengaRu [80]

Answer:

1 km / 15min

Explanation:

The average speed is calculated by simply doing space divided by time so:

2km / 30min that becomes 1km / 15min

Have a good day.

3 0

2 years ago

A 0.500-kg potato is fired at an angle of 80.0° above the horizontal from a PVC pipe used as a "potato gun" and reaches a height

lions [1.4K]

Answer:

(a) $47.15ms^{-1}$

(b) $2470.13ms^{-2}$

Explanation:

From Newton's second law of motion

F=ma where m is mass, a is acceleration and F is net force

Also from kinetic equation of motion, velocity and displacement are related using equation

$v^{2}=u^{2}+2sa$

Where v is final velocity, u is initial velocity, a is acceleration and s is displacement

From the free body diagram attached, final velocity at maximum height is 0 and initial velocity is $usin80^{o}$

Also, the vertical component can be written as

$v_{y}^{2} }=u_{y}^{2} } -2gs$ The negative sign before 2gs means displacement is opposite the gravitational force

Where g is acceleration due to gravity, $u_{y}$ is vertical component of initial velocity and $v_{y}$ is vertical component of final velocity

Since $v_{y}$ is 0

$u_{y}^{2} } =2gs$

s=110 and g is taken as 9.8

$u_{y}=\sqrt{2*9.8*110}=46.43275$

$u_{y}=46.43ms^{-1}$

Also, it's evident that the vertical component of initial velocity is $u_{y}=u_{i}sin \theta$ where $\theta$ is angle of projection and $u_{i}$ is resultant velocity