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3 years ago

Fire andwater ______(do/does) not agree

Engineering

1 answer:

Elina [12.6K]3 years ago

3 0

Answer:

Hii Dear !!! 

How are you ....

I hope That you are Fine .....

Explanation:

So the answer is __does_____

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At the grocery store you place a pumpkin with a mass of 12.5 lb on the produce spring scale. The spring in the scale operates su

UkoKoshka [18]

Answer:

x=2.19in

Explanation:

This is the equation that relates the force and displacement of a spring

F=Kx

m=mass=12.5lbx1slug/32.14lb=0.39slug

F=mg=0.39*32.2=12.52Lbf

then we calculate the spring count in lbf / ft

K=F/x

K=5.7lbf/1in=5.7lbf/in=68.4lbf/ft

Finally we calculate the displacement with the initial equation

X=F/k

x=12.52/68.4=0.18ft=2.19in

8 0

4 years ago

Danny is looking at deploying a new application that requires root-level access to the server. He is currently researching the c

Advocard [28]

Answer:

Option C (IaaS) will be the correct answer.

Explanation:

IaaS is essentially a cloud strategy that enables an individual or company to rent resources including such servers, networking devices including data or storage management. IaaS is a digital storage facility.
PaaS can not provide root privileges as even the hosting company would control the network. Here, SaaS as well as DBaaS aren't important.

That will be the right answer to the question.

4 0

3 years ago

A compressed-air drill requires an air supply of 0.25 kg/s at gauge pressure of 650 kPa at the drill. The hose from the air comp

Klio2033 [76]

Answer:

L = 46.35 m

Explanation:

GIVEN DATA

\dot m = 0.25 kg/s

D = 40 mm

P_1 = 690 kPa

P_2 = 650 kPa

T_1 = 40° = 313 K

head loss equation

$[\frac{P_1}{\rho} +\alpha \frac{v_1^2}{2} +gz_1] -[\frac{P_2}{\rho} +\alpha \frac{v_2^2}{2} +gz_2] = h_l +h_m$

where $h_l = \frac{ flv^2}{2D}$

$h_m minor loss$

density is constant

$v_1 = v_2$

head is same so, $z_1 = z_2$

curvature is constant so $\alpha = constant$

neglecting minor losses

$\frac{P_1}{\rho} -\frac{P_2}{\rho} = \frac{ flv^2}{2D}$

we know $\dot m$ is given as $= \rho VA$

$\rho =\frac{P_1}{RT_1}$

$\rho =\frac{690 *10^3}{287*313} = 7.68 kg/m3$

therefore

$v = \frac{\dot m}{\rho A}$

$V =\frac{0.25}{7.68 \frac{\pi}{4} *(40*10^{-3})^2}$

V = 25.90 m/s

$Re = \frac{\rho VD}{\mu}$

for T = 40 Degree, $\mu = 1.91*10^{-5}$

$Re =\frac{7.68*25.90*40*10^{-3}}{1.91*10^{-5}}$

Re = 4.16*10^5 > 2300 therefore turbulent flow

for Re =4.16*10^5 , f = 0.0134

Therefore

$\frac{P_1}{\rho} -\frac{P_2}{\rho} = \frac{ flv^2}{2D}$

$L = \frac{(P_1-P_2) 2D}{\rho f v^2}$

$L =\frac{(690-650)*`10^3* 2*40*10^{-3}}{7.68*0.0134*25.90^2}$

L = 46.35 m

5 0

3 years ago

How does a belt operated supercharger work? (Not a turbo charger)

icang [17]

Answer:

A root-type supercharger works similar to that of an air pump. It pumps air into the intake of the engine. Within the engine cylinder, the compression of the air-fuel mixture takes place. A centrifugal supercharger, works like a turbo, compresses the air in it and then delivers it to the engine.

3 0

3 years ago

Select the correct answer from each drop-down menu.

weeeeeb [17]

Answer:

In engineering, the most basic or primary unit of measurement used for drafting is the millimeter and the meter, followed by the kilometer

Explanation:

Based on the the SI system of units, in engineering, the most basic or primary unit of measurement used for drafting is the millimeter and the meter, followed by the kilometer

The millimeter is used in mechanical and an architectural drawing, the meter is used architectural drawing, while civil dimensioning make use of the kilometer

In the US it is customary to use the inches and a fraction of an inch is used as a scale in scale drawings

8 0

3 years ago

Fire andwater ______(do/does) not agree​

Fire andwater ______(do/does) not agree