Explanation:
A.
H = Aeσ^4
Using the stefan Boltzmann law
When we differentiate
dH/dT = 4AeσT³
dH/dT = 4(0.15)(0.9)(5.67)(10^-8)(650)³
= 8.4085
Exact error = 8.4085x20
= 168.17
H(650) = 0.15(0.9)(5.67)(10^-8)(650)⁴
= 1366.376watts
B.
Verifying values
H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(670)⁴
= 1542.468
H(T+ΔT) = 0.15(0.9)(5.67)(10^-8)(630)⁴
= 1205.8104
Error = 1542.468-1205.8104/2
= 168.329
ΔT = 40
H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(690)⁴
= 1735.05
H(T-ΔT) = 0.15(0.9)(5.67)(10^-8)(610)⁴
= 1735.05-1059.83/2
= 675.22/2
= 337.61
Answer:
a) ∝ and β
The phase compositions are :
C
= 5wt% Sn - 95 wt% Pb
C
= 98 wt% Sn - 2wt% Pb
b)
The phase is; ∝
The phase compositions is; 82 wt% Sn - 91.8 wt% Pb
Explanation:
a) 15 wt% Sn - 85 wt% Pb at 100⁰C.
The phases are ; ∝ and β
The phase compositions are :
C
= 5wt% Sn - 95 wt% Pb
C
= 98 wt% Sn - 2wt% Pb
b) 1.25 kg of Sn and 14 kg Pb at 200⁰C
The phase is ; ∝
The phase compositions is; 82 wt% Sn - 91.8 wt% Pb
Csn = 1.25 * 100 / 1.25 + 14 = 8.2 wt%
Cpb = 14 * 100 / 1.25 + 14 = 91.8 wt%
Answer:
One
For surface-mounted and pendant-hung luminaires, support rods should be placed so that they extend about _one___
<h3>what is supported mounted?</h3>
- A structure that holds up or serves as a foundation for something else. Support is a synonym for mounting.
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The resources and instructions that should be used for the procedures of performing PMCS are:
- Operator's manuals
- Safety cautions and warnings.
- Fording kit
- Heating and cooling systems.
<h3>What is PMCS?</h3>
PMCS is an acronym for preventive maintenance checks and services and it can be defined as the maintenance, checks, and services that are typically performed before, during, and after the use of any type of military equipment such as:
Basically, the resources and instructions that should be used for the procedures of performing PMCS are:
- Operator's manuals
- Safety cautions and warnings.
- Fording kit
- Heating and cooling systems.
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Answer:
x = 93.8 m.
Explanation:
During the entire the reaction time interval, the vehicle continues moving at the same speed that it was moving, i.e., 60 mi/hr.
In order to calculate the distance in meters, travelled at that speed, it is advisable first to convert the 60 mi/hr to m/seg, as follows:

Applying the definition of average velocity, we can solve for Δx, as follows:
Δx = 26.8 m/s* 3.5 s = 93.8 m