<u>Answer:</u>
a) Height of cliff = 44.145 meter
b) 7.5 meter far from its base the diver hit the water.
<u>Explanation:</u>
We have equation of motion , 
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Diver's vertical motion:
Initial velocity = 0 m/s, acceleration = 9.8 
, we need to calculate displacement when time is 3 seconds.
So height of cliff = 44.145 meter.
b) Diver's horizontal motion:
Initial velocity = 2.5 m/s, acceleration = 0 , we need to calculate displacement when time is 3 seconds.
So 7.5 meter far from its base the diver hit the water.
Answer:
<h2>2 m/s²</h2>
Explanation:
The acceleration of an object given it's velocity and time taken can be found by using the formula
v is the velocity
t is the time taken
From the question we have
We have the final answer as
<h3>2 m/s²</h3>
Hope this helps you
Answer:complex
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Answer · 38 votes
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MoreExplanation:thats it!!!! i <em>guessed∦∩⊕</em>
The answer is B as all the other options contain quantities not related to describing motion
45 hours/15 hours = 3 Half lifes
50/2 = 25
25/2 = 12.5
12.5/2 = 6.25
6.25g is the answer
