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Dmitriy789 [7]
3 years ago
14

In a lab environment, you are investigating the impulse of a force exerted on a brick when the brick's speed is reduced from 2.5

m/s to a complete stop. First, you allow the brick to slam into a secured piece of wood, bringing the brick to a sudden stop. Second, you allow the brick to plow into a large slab of gelatin so that the brick comes to a gradual halt. In which situation is there a greater impulse of the force on the brick?
The impulse is the same in both situations.
There is a greater impulse of the force on the brick from the gelatin.
Not enough information is given to determine the answer.
There is a greater impulse of the force on the brick from the wall.
Physics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer:

The impulse is the same in both situations.

Explanation:

As we know that impulse is defined as change in momentum

so it is given as

\Delta P = m(v_f - v_i)

also we know that

\Delta P = F\Delta t

so we will have

v_f = 0

v_i = 2.5 m/s

now impulse is given as

\Delta P = m(2.5 - 0)

so it is independent of the time for which it is stopped

so impulse will be same in both cases

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Explanation:

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A ball is rolling across the floor at a constant speed. What will happen to the ball if it is exposed
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La tension que se transmite en la cuerda BD es de 75 lb. Calcula el momento de fuerza generada por la cuerda respecto al punto C
Bas_tet [7]

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Mc = 1920[lb*in]

Explanation:

Para poder solucionar este problema debemos realizar un análisis estático, por tal motivo lo primero es realizar un diagrama de cuerpo libre con las respectivas fuerzas actuando sobre la barra ABC. DE igual manera calcular la geometría de la configuración mostrada.

El diagrama de cuerpo libre se puede ver en la imagen adjunta, con la solución de este problema.

Lo primero es determinar el angulo t, el cual por medio de las propiedades del triangulo rectángulo se puede determinar.

Con este angulo (t) ya determinado, fijamos la atención en el triangulo BCD, este triangulo no es rectángulo, pero por medio de la ley de senos podemos determinar el angulo omega.

Después de determinar el angulo omega, restamos el angulo (t) para poder determinar el angulo (a).

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