A sled of mass 28 kg slides across the ground with a friction force of 200.3 N. What is k between the sled and the ground?

1 answer:

3 0

K=Frictional Force/Normal Force
Normal force would be mg, since it's not on an incline.
Normal Force = 28 kg*9.8 m/s^2 = 274.4 N

200.3 N/274.4 N = 0.73

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NB: The figure is not provided but all the parameters needed to solve the question have been given.

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