1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scilla [17]
3 years ago
8

The gravitational force between two objects increases as mass

Physics
2 answers:
nasty-shy [4]3 years ago
7 0
F=g(m1*m2)/r^2
gravitational force is directly proportional to product of masses and inversely proportional to square of distance between them.so consequently mass should increase and distance should decrease
Bezzdna [24]3 years ago
6 0
The gravitational force between two objects increases as mass increases or distance decreases. This will make the correct answer C. 
You might be interested in
A 0.40-kg mass, attached to the end of a 0.75-m string, is whirled around in a circular horizontal path. If the maximum tension
hichkok12 [17]

To solve this problem we will apply the concepts given from the circular movement of the bodies for which we have that the centripetal Force is defined as a product between the mass and the velocity squared at the rate of rotation, mathematically this is

F_c = \frac{mv^2}{r}

Where,

m = Mass

v = Velocity

r = Radius

Our values are given as

m = 0.4kg\\r = 0.75m\\F_c = 450N

Rearranging to find the velocity we have that,

F_c = \frac{mv^2}{r}

v = \sqrt{\frac{F_c * r}{m}}

v = \sqrt{\frac{450 * 0.75}{0.4}}

v = 29.0474m/s

Therefore the  maximum speed can the mass have if the string is not to break is 29m/s

3 0
3 years ago
Hello!
Mnenie [13.5K]

Answer:

T_0=80695.17162...

Explanation:

Given equation:

\ln \left(\dfrac{T_0-100}{T_0}\right)=-0.00124

To solve the given equation:

\textsf{Apply log rules}: \quad e^{\ln (x)}=x

\implies \dfrac{T_0-100}{T_0}=e^{-0.00124}

Multiply both sides by T₀:

\implies T_0-100=T_0e^{-0.00124}

Add 100 to both sides:

\implies T_0=T_0e^{-0.00124}+100

Subtract T_0e^{-0.00124} from both sides:

\implies T_0-T_0e^{-0.00124}=100

Factor out the common term T₀:

\implies T_0(1-e^{-0.00124})=100

Divide both sides by (1-e^{-0.00124})

\implies T_0=\dfrac{100}{1-e^{-0.00124}}

Carry out the calculation:

\implies T_0=\dfrac{100}{1-0.99876...}

\implies T_0=\dfrac{100}{0.001239231...}

\implies T_0=80695.17162...

6 0
3 years ago
A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the
Furkat [3]

Answer:

75 Newtons.

Explanation:

From Newton's second law of motion,

F = m(v-u)/t................... Equation 1

Where F = force exerted by the ball on the bat, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time

Given: m = 0.6 kilogram, u = 0 meter per seconds (at rest), v = 25 meters per seconds, t = 0.2 seconds.

Substitute into equation 1

F = 0.6(25-0)/0.2

F = 3(25)

F = 75 Newton.

Hence the magnitude of the average force exerted by the ball on the bat = 75 Newtons.

8 0
4 years ago
The scientific method is
pashok25 [27]
The conclusion of a scientific process is a statement of whether the original hypothesis was supported or refuted by the observations gathered.

The six steps are:
1) Make an observation
2) Ask a question
3) Form a hypothesis
4) Conduct an experiment
5) Accept or Reject the hypothesis
6) Share your results
7 0
4 years ago
11. Highlight your answer: In a double slit experiment with slits 1.00x10^-5m apart, light casts the first bright
grin007 [14]

Answer:

λ  ≈ 462 nm  

Explanation:

Given:-

- The slit separation, a = 10^-5 m

- The first bright fringe occurs at, y = 0.03 m from central order

- The distance between the screen and slit, L = 0.65 m

Find:-

what is the wavelength of  this light?

Solution:-

- The Young's double slit experiment gives us the relation for the interaction of a light with wavelength ( λ ) that pass through 2-slits with separation ( a ) and interfere constructively or destructively at the the screen Hence, forming an interference pattern of bright and dark fringes.

- The relation for separation ( y ) between bright fringes is related to the above mentioned parameters as given below:

                      y = L*n*λ / a

Where,

                 n: The order of fringe from central

Re-arrange for wavelength ( λ ).

- The order of first bright fringe is n = 1:

                      λ  = y*a / L

                      λ  = 0.03*0.00001 / 0.65

                      λ  = 4.61538 * 10^-7 m

                      λ  ≈ 462 nm  

6 0
4 years ago
Other questions:
  • To view an interactive solution to a problem that is similar to this one, select Interactive Solution 7.24. A 0.0146-kg bullet i
    10·1 answer
  • In which of the following scenarios does object 1 do +10 joules of work on object 2?
    8·1 answer
  • A mxiture of n2 and H2 has mole fraction of 0.4 and 0.6 respectively. Determine the density of the mixture at one bar and 0 c.
    11·1 answer
  • Astronomers infer that the universe is expanding because distant galaxies all appear to ________. Astronomers infer that the uni
    15·1 answer
  • REM sleep
    10·1 answer
  • Four resistors of 12, 3.0, 5.0, and 4.0 Ω are connected in parallel. A 12-V battery is connected to the combination. What is the
    9·1 answer
  • If the orbital velocity of a satellite is 2 rad/s then what will be the period of satellite.
    12·1 answer
  • A man wishes to travel due north in order to cross a river 5 kilometers wide flowing due East at 3 kilometers per hour . if he c
    9·1 answer
  • The diagram below represents the forces acting upon a rightward-moving object.
    14·1 answer
  • Part F What are some potential applications of a material that make things invisible?​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!