Answer:
2.58 x 10⁸ m/s
Explanation:
Time dilation fomula will be applicable here, which is given below.
t = \frac{T}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}
Where T is dilated time or time observed by clock in motion , t is stationary time , v is velocity of clock in motion and c is velocity of light .
c is 3 times 10⁸ ms⁻¹ , T is 7.24 h , t is 3.69 h. Put these values in the formula
7.24 = \frac{3.69}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}\\
\frac{v^2}{c^2}=0.744\\\\
v=2.58\times 10^8
Answer:
585 nm
Explanation:
The formula that gives the position of the m-th maximum (bright fringe) relative to the central maximum in the interference pattern produced by diffraction from double slit is:
where
m is the order of the maximum
is the wavelength
D is the distance of the screen from the slits
d is the separation between the slits
The distance between two consecutive bright fringes therefore is given by:
In this problem we have:
(distance between two bright fringes)
D = 2.0 m (distance of the screen)
d = 3.0 x 10−3 m (separation between the slits)
Solving for , we find the wavelength:
Answer:
The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Explanation:
Given;
number of turns of the flat circular loop, N = 18 turns
radius of the loop, R = 15.0 cm = 0.15 m
current through the wire, I = 0.51 A
The magnetic field through the center of the loop is given by;
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Answer:
80 ft/s
Explanation:
Given:
Δy = 100 ft
v₀ = 0 ft/s
a = 32.2 ft/s²
Find: v
v² = v₀² + 2aΔx
v² = (0 ft/s)² + 2 (32.2 ft/s²) (100 ft)
v = 80.2 ft/s
Rounded, the speed when it reaches the ground is 80 ft/s.
Answer:
304.89m
Explanation:
Given
acceleration a = 2.52m/s²
final speed v = 39.2m/s
initial speed = 0m/s (car accelerates from rest)
Using the equation of motion below to get the distance of Doc brown from Marty;
v² = u²+2as
substitute the given parameters
39.2² = 0²+2(2.52)s
1536.64 = 0+5.04s
divide both sides by 5.04
1536.64/5.04 = 5.04s/5.04
rearrange the equation
5.04s/5.04 = 1536.64/5.04
s = 304.89m
Hence He and Marty must stand at 304.89m to allow the car to accelerate from rest to a speed of 39.2 m/s?
