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tankabanditka [31]
1 year ago
6

A. Label the following properties on the wave below: rarefaction, wavelength, and compression. (Image attached)

Physics
2 answers:
DedPeter [7]1 year ago
0 0

PART a)

Rarefraction : It is the region of lower density where particles move away from each other

Wavelength : distance between two consecutive compression or rarefaction is known as wavelength

Compression : The region of higher density or the region where particles comes closer to each other is compression

Part b)

Here it is given that

f = 2100 Hz

\lambda = 3.0 m

So here we know that

wave speed = frequency \times wavelength

[tex]v = 2100(3) = 6300 m/s

PART c)

As the person drop the stone in the water it creates waves on the surface of water

These waves can move the boat up and down at its own position and it can not displace the boat so it will not move to the shore

PART D)

When stone is dropped in the water it creates waves. these waves when travel through the water and disturb the boat

Due to this disturbance boat starts moving up and down at its own position and it will not displace from its position.

So by this type of waves it will not move towards the shore

Alecsey [184]1 year ago
0 0

a) Rarefactions are in the green frames, compressions in the purple. Wavelength is a distance between same points of the two corresponding rarefactions/compressions.

b) v=wavelength times frequency=3*2100= 6300 m/s.

c) Bad idea that most likely won't work. Waves on water move only in vertical direction. But maybe a high wave will lift the boat and rescue it.

d) Ah, he needs wants the boat reach the shore, I thought it stuck and the person just wants to make it float. Yes, that's not the best idea, see explanation above

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Alekssandra [29.7K]

Answer:

0.40s. He's dead, Jim.

Explanation:

The block accelerates at a rate of 9.81 ms^-^2. The moment it's 14 meters from the ground, it has traveled 39 meters, in about 39=\frac12(9.81)t^2 \rightarrow 2.82 s.

For the man to dodge, the time left is the distance the block takes to go down to 2 meters from ground, or 51 meters from its starting point. Which translates in 51=\frac12(9.81)t^2\rightarrow 3.22s

He has thus less than half a second (0.40s to be exact) to dodge.

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