A. Label the following properties on the wave below: rarefaction, wavelength, and compression. (Image attached)
2 answers:
PART a)
Rarefraction : It is the region of lower density where particles move away from each other
Wavelength : distance between two consecutive compression or rarefaction is known as wavelength
Compression : The region of higher density or the region where particles comes closer to each other is compression
Part b)
Here it is given that
So here we know that
[tex]v = 2100(3) = 6300 m/s
PART c)
As the person drop the stone in the water it creates waves on the surface of water
These waves can move the boat up and down at its own position and it can not displace the boat so it will not move to the shore
PART D)
When stone is dropped in the water it creates waves. these waves when travel through the water and disturb the boat
Due to this disturbance boat starts moving up and down at its own position and it will not displace from its position.
So by this type of waves it will not move towards the shore
a) Rarefactions are in the green frames, compressions in the purple. Wavelength is a distance between same points of the two corresponding rarefactions/compressions.
b) v=wavelength times frequency=3*2100= 6300 m/s.
c) Bad idea that most likely won't work. Waves on water move only in vertical direction. But maybe a high wave will lift the boat and rescue it.
d) Ah, he needs wants the boat reach the shore, I thought it stuck and the person just wants to make it float. Yes, that's not the best idea, see explanation above
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The distance of the motorboat relative to the home, which travels in various directions, is 3.07 km.
<h3>What is relative velocity?</h3>Relative velocity is a velocity of an object which is in respect to another observer, or it is a ratio of change in the position of a point to time with respect to another observer.
Given: Travel in East direction ()= 5 km,
velocity in N35E(v) = 2 m / s, time taken(t) = 90 min = 5400 seconds,
Displacement in south () = 6.5 km
Firstly, find the displacement in N35E so
Displacement = Velocity × time,
= 2 × 5400 = 10800 meters or 10.8 km
Now by using Pythagoras' theorem
We can calculate the return displacement in the south direction(),
=
=
= 9.57 km
Therefore, the distance of the boat from the home (D) = -
D = 9.57 - 6.5;
D = 3.07 Km
To know more about Relative velocity:
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Answer:
(A) 4.09 kg/s
(B) 589.9 m/s
(C) 0.0008707 m^{3} = 8.71 cm^{2}
Explanation:
inlet pressure of steam (P1) = 4 MPa
inlet temperature of steam (T1) = 400 degree celcius
inlet velocity (V1) = 60 m/s
outlet pressure (P2) = 2 MPa
outlet temperature (T2) = 300 degree celcius
inlet area (A1) = 50 cm^{2} = 0.005 m^{2}
rate of heat loss (Q) = 75 kJ/s
(A) mass flow rate (m) = \frac{A1 x V1}{α1}
where the initial specific volume (α1) for the given temperature and pressure is gotten from tables A-6 = 0.07343 m^3/kg
m = \frac{0.005 x 60}{0.07343}
m = 4.09 kg/s
(B) we can get the outlet velocity using the energy balance equation
E in = E out
m(h1 + \frac{(V1)^{2}}{2}) = m(h2 + \frac{(V2)^{2}}{2})
V2 =
where h1 and h2 are the enthalpies and are gotten from table A-6
V2 =
V2 = 589.9 m/s
(C) the outlet area is gotten from mass flow rate (m) = \frac{A2 x V2}{α}
A2 = (α2 x m) / V2
where the initial specific volume (α2) for the given temperature and pressure is gotten from tables A-6 = 0.12552 m^3/kg
A2 = (0.12552 x 4.09) / 589.5 = 0.0008707 m^{3} = 8.71 cm^{2}