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3 years ago

Are energy changes always involved when substances dissolved in water

1 answer:

8 0

Yes i believe there are energy changes when substances are dissolved in water which are either exothermic or endothermic. When a substance is dissolved in water and temperature goes up, heat is released or produced which is called exothermic change. Most substances dissolve in water lowering the temperature and are endothermic changes as energy is absorbed. For example when sodium chloride dissolves in water there is very little change in temperature which is exothermic.

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Calculate the molarity of a sugar solution if 4 liters of the solution contains 12 moles of sugar.

castortr0y [4]

Answer:

Explanation:

Molarity is one of the measures of the molar concentration of a solution, which can be calculated by using the formula below:

Molarity = number of moles ÷ volume

From the information given in this question, 4 liters of a solution contains 12 moles of sugar. This means that n = 12mol and V = 4L

Molarity = n/V

Molarity = 12/4

Molarity = 3

Hence, the molarity of the sugar solution is 3mol/L or 3M

8 0

2 years ago

1. How many Chromium atoms are found in 25.8 milligrams of Chromium?

givi [52]

Answer: 51.9961 g/mol, don't know if it helps :)

Explanation:

7 0

3 years ago

Read 2 more answers

A 13 g sample of P4010 contains how many

Alex777 [14]

Answer:

$\large \boxed{5.5 \times 10^{22}\text{ molecules of P$_{2}$O}_{5}}$

Explanation:

You must calculate the moles of P₄O₁₀, convert to moles of P₂O₅, then convert to molecules of P₂O₅.

1. Moles of P₄O₁₀

$\text{Moles of P$_{4}$O}_{10} = \text{13 g P$_{4}$O}_{10} \times \dfrac{\text{1 mol P$_{4}$O}_{10}}{\text{283.89 g P$_{4}$O}_{10}} = \text{0.0458 mol P$_{4}$O}_{10}$

2. Moles of P₂O₅

P₄O₁₀ ⟶ 2P₂O₅

The molar ratio is 2 mol P₂O₅:1 mol P₄O₁₀

$\text{Moles of P$_{2}$O}_{5} = \text{0.0458 mol P$_{4}$O}_{10} \times \dfrac{\text{2 mol P$_{2}$O}_{5}}{\text{1 mol P$_{4}$O}_{10}} = \text{0.0916 mol P$_{2}$O}_{5}$

3. Molecules of P₂O₅

$\text{No. of molecules} = \text{0.0916 mol P$_{2}$O}_{5} \times \dfrac{6.022 \times 10^{23}\text{ molecules P$_{2}$O}_{5}}{\text{1 mol P$_{2}$O}_{5}}\\\\= \mathbf{5.5 \times 10^{22}}\textbf{ molecules P$_{2}$O}_{5}\\\text{There are $\large \boxed{\mathbf{5.5 \times 10^{22}}\textbf{ molecules of P$_{2}$O}_{5}}$}$

6 0

3 years ago

A solution of LiCl in water has XLiCl = 0.0800. What is the molality? A solution of LiCl in water has XLiCl = 0.0800. What is th

Kay [80]

Answer:

mol LiCl = 4.83 m

Explanation:

GIven:

Solution of LiCl in water XLiCl = 0.0800

Mol of water in kg = 55.55 mole

Find:

Molality

Computation:

mole fraction = mol LiCl / (mol water + mol LiCl)

0.0800 = mol LiCl / (55.55 mol + mol LiCl)

0.0800 mol LiCl + 4.444 mol = mol LiCl

mol LiCl - 0.0800 mol LiCl = 4.444 mol

0.92 mol LiCl = 4.444 mol

mol LiCl = 4.83 m

7 0

3 years ago

Will bromine react with sodium

denis-greek [22]

Yes. bromine and sodium iodide can react to form sodium bromine and free iodine

4 0

2 years ago