Answer: 2738
Explaining: you gotta add
The number of moles of b2o3 that will be formed is determined as 4 moles.
<h3>
Limiting reagent</h3>
The limiting reagent is the reactant that will be completely used up.
4 b + 3O₂ → 2b₂O₃
from the equation above;
4 b ------------> 2 b₂O₃
2b ------------> b₂O₃
2 : 1
3O₂ -------------> 2b₂O₃
3 : 2
b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;
4 b ------------> 2 moles of b2o3
8 moles -------> ?
= (8 x 2)/4
= 4 moles
Thus, the number of moles of b2o3 that will be formed is determined as 4 moles.
Learn more about limiting reactants here: brainly.com/question/14222359
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486 kPa will be the pressure of gas at 27 degrees.
Explanation:
Data given :
Initial pressure of the gas P1 = 810 kPa
initial temperature of the gas T1 = 227 degrees OR 500.15 K
final pressure of the gas =?
final temperature of the gas = 27 degrees OR 300.15 K
Gay Lussac's law is used to calculate the pressure of the gas at 27 degrees or 300.15 K
= 
P2 = 
Putting the values in the equation:
P2 = 
P2 = 486 KPa
486 Kpa is the pressure of the gas when temperature was reduced to 27 degrees.
the molarity of KCl solution prepared by dissolving 0.898 mole of KCl in 250 ml water is calculated using the below formula
molarity= moles/volume in liters
moles= 0.898 moles
volume in liters= 250/1000 =0.25 liters
molarity is therefore= 0.898/0.25= 3.592 M
