Answer:
1.2 s
Explanation:
We'll begin by calculating the length (i.e distance) of the ramp. This can be obtained by using pythagoras theory as illustrated below:
NOTE: Length of the ramp is the Hypothenus i.e the longest side.
Let the Lenght of the ramp be 's'. The value of x can be obtained as follow:
s² = 4² + 3²
s² = 16 + 9
s² = 25
Take the square root of both side
s = √25
s = 5 m
Thus the length of the ramp is 5 m
Next, we shall determine the final velocity of the ball. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Distance (s) = 5 m
Final velocity (v) =?
v² = u² + 2as
v² = 3² + (2 × 2 × 5)
v² = 9 + 20
v² = 29
Take the square root of both side
v = √29
v = 5.39 m/s
Finally, we shall determine the time taken for the ball to reach the final position. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Final velocity (v) = 5.39 m/s
Time (t) =?
v = u + at
5.39 = 3 + 2t
Collect like terms
5.39 – 3 = 2t
2.39 = 2t
Divide both side by 2
t = 2.39 / 2
t = 1.2 s
Thus, it will take 1.2 s for the ball to get to the final position.
Answer:
W = 750 Joules.
Explanation:
Given that,
Force acting on the object, F = 50 N
Distance moved by the object, d = 15 m
To find,
Work done by the object
Solution,
Let W is the work done by the object. It is given by the product of force and distance. Its expression is given by :
Here, 
(force and distance are in same direction)
W = 750 Joules
So, the work done by the force is 750 Joules.
I would say d because the student isn’t moving, the Ferris wheel is.
Answer:
because of the idea that like charges get repulsion as a force.
Explanation:
because you wrap the ball with foil, the negative charges will leave the foil and go into the ball by induction. This leaves the foil as a positively charged particle since its electrons left it for the ball, making the ball a negatively charged particle. but if you bring the negative charge near the foil, the electrons will transfer from that and go into the foil, making it negatively charged. Now, because the ball and the foil have the same charge, they repel. the foil flies off.
The distance from the base of the building the rock will land is 26.4 m
<h3>Data obtained from the question </h3>
- Horizontal velocity (u) = 20 m/s
- Height (h) = 8.50 m
- Distance (s) =?
<h3>Determination of the time to reach the ground </h3>
- Height (h) = 8.50 m
- Acceleration due to gravity (g) = 9.8 m/s²
- Time (t) =?
h = ½gt²
8.5 = ½ × 9.8 × t²
8.5 = 4.9 × t²
Divide both side by 4.9
t² = 8.5 / 4.9
Take the square root of both side
t = √(8.5 / 4.9)
t = 1.32 s
<h3>How to determine the distance </h3>
- Horizontal velocity (u) = 20 m/s
- Time (t) = 1.32 s
- Distance (s) =?
s = ut
s = 20 × 1.32
s = 26.4 m
Learn more about motion under gravity:
brainly.com/question/22719691
