Answer:
ρ/ρ2 = 3 / R₀ the two densities are different
Explanation:
Density is defined as
ρ = M / V
As the nucleus is spherical
V = 4/3 π r³
Let's replace
ρ = A / (4/3 π R₀³)
ρ = ¾ A / π R₀³
b)
ρ2 = F / area
The area of a sphere is
A = 4π R₀²
ρ2 = F / 4π R₀²
ρ2 = F / 4π R₀²
Atomic number is the number of protons in the nucleon in not very heavy nuclei. This number is equal to the number of neutrons, but changes in heavier nuclei, there are more neutrons than protons.
Let's look for the relationship of the two densities
ρ/ρ2 = ¾ A / π R₀³ / (F / 4π R₀²)
ρ /ρ2 = 3 (A / F) (1 / R₀)
In this case it does not say that the nucleon number is A (F = A), the relationship is
ρ/ρ2 = 3 / R₀
I see that the two densities are different
It would be 20 protons left because 1-19= 20
Answer:
Amplitude = 0.02m
Frequency = 640 Hz
Wavelength, λ = 0.5m
v = 320 m/s
Explanation:
Given the wave equation :
y=0.02 sin2π/0.5 (320t - x) where x and y are in
meters and t is in second
Comparing the above relation with the general wave equation :
y(x, t) = Asin2π/λ(wt - kx)
The amplitude, A = 0.02
From the equation :
2π/0.5 = 2π/λ
λ = 0.5 m
320t = vt
Hence, v = 320 m/s
Recall :
v = fλ
320 = f * 0.5
f = 320 / 0.5
f = 640 Hz
