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3 years ago

What would happen if there was no friction between a rolling ball and the ground

Physics

1 answer:

Juli2301 [7.4K]3 years ago

6 0

Answer: It would oppose motion

Explanation:

if something would be sliding or rolling across the floor, the friction would for example make that ball stop rolling and so without the friction the rolling ball will just continue to roll for i do not know how long cause there would be no friction to stop it so it would be the opposite of what friction does so it would be oppose motion.

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A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Teflon frying p

IRINA_888 [86]

Answer:

normal force = 10 N

Explanation:

Given data

frictional force = 0.400 N

coefficient of kinetic friction = 0.04

Solution

we get here normal force that is express as

normal force = $\frac{Frictional\ force}{coefficient\ of\ friction}$ ............1

put here value and we will get value

normal force = $\frac{0.400}{0.04}$

solve it we get

normal force = 10 N

5 0

3 years ago

Please I need with this

guajiro [1.7K]

I think its b im not sure im in 8th grade

8 0

3 years ago

A person exerts a tangential force of 37.7 N on the rim of a disk-shaped merry-go-round of radius 2.75 m and mass 144 kg. If the

Shkiper50 [21]

Answer:

ω = 0.467 rad/s

Explanation:

given,

tangential force exerted by the person = 37.7 N

radius of merry-go-round = 2.75 m

mass of merry-go-round = 144 Kg

angle = 33.2°

moment of inertia

$I = \dfrac{1}{2} m R^2$

$I = \dfrac{1}{2}\times 144 \times 2.75^2$

I = 544.5 kg.m²

torque = force x radius

τ = 37.7 x 2.75

τ = 103.675 N.m

angular acceleration

$\alpha= \dfrac{\tau}{I}$

$\alpha= \dfrac{103.675}{544.5}$

α = 0.190 rad/s²

now ,

distance = $33.2\times \dfrca{2\pi}{360}$

d = 0.579 rad

we know,

using equation of rotational motion

$d = \omega t + \dfrac{1}{2}\alpha t^2$

$0.579 = \dfrac{1}{2}\times 0.190\times t^2$

t = 2.46 s

angular speed

ω = α x t

ω = 0.19 x 2.46

ω = 0.467 rad/s

7 0

3 years ago

Plzzz someone help me!!!!.

Vlad [161]

Answer:

He could re read his answear.

Explanation:

4 0

3 years ago

A car that is standing still accelerates up a hill with a slope of 6.4% at an average acceleration of 2.93 ft/s^2. The hill is 1

alexgriva [62]

Answer:

213 s

Explanation:

Slope is the ratio of change in vertical distance to change in horizontal distance.

Slope = vertical height / horizontal height

Therefore:

6.4% = vertical height / 12.42

vertical height = 6.4% * 12.42

vertical height = 0.8 miles

The distance travelled by the car (s) is:

s² = 0.8² + 12.42²

s² = 154.9

s = 12.45 miles

Acceleration (a) = 2.93 ft/s^2 = 0.00055 mile/s²

initial velocity (u) = 0, final velocity = 203 mph

Using:

s = ut + 0.5at²

12.45 = 0.5(0.00055)t²

t =213 s

5 0

3 years ago