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dem82 [27]
3 years ago
14

List the following from least complex to most complex: Bacterial Cell, Multicellular Organism, and Cell with a nucleus

Chemistry
1 answer:
cluponka [151]3 years ago
6 0
Bacterial cell, cell with a nucleus, multicellular organism
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Answer: A (Bicycling)

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2 years ago
What might be a scientific question
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Example of a scientific question:

Does the angle of a ramp change the distance a toy car will travel?

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2 years ago
Shown below is a table with plants and animals with their adaptations.
zhenek [66]

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Desert

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The adaptation shown by the given plants and animals shows that they will adapted to the desert biome.

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8 0
3 years ago
How many mL of 2.0 M KOH are necessary to neutralize 50 mL of 1 M HCl?
worty [1.4K]

Answer:

25mL

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Please see the step-by-step solution in the picture attached below.

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6 0
3 years ago
Muscle physiologists study the accumulation of lactic acid [ch3ch(oh)cooh] during exercise. food chemists study its occurrence i
Drupady [299]
The provided information are:
volume of 0.85 M lactic acid = 225 ml
volume of 0.68 M sodium lactate = 435 ml
Ka of the lactate buffer = 1.38 x 10⁻⁴
 The equation for dissociation of lactic acid is:
CH₃CH(OH)COOH(aq) + H₂O ⇄ CH₃CH(OH)COO⁻(aq) + H₃O⁺(aq)
The pH of buffer is calculated from Henderson-Hasselbalch equation, which is:
pH = pKa + log \frac{[conjugated base]}{[Acid]}
pKa = - log Ka = - log (1.38 x 10⁻⁴) = 3.86 
The number of moles of lactic acid and lactate are as follows:
n (Lactic acid) = 225 ml x 0.85 mmol/ml = 191.25 mmol
n (Lactate) = 435 ml x 0.68 mmol/ml = 295.8 mmol
The number of moles of lactic acid and lactate in total volume of the solution:
[CH₃CH(OH)COOH] = n (lactic acid) / 660 ml = 191.25 mmol / 660 ml = 0.29 M
[CH₃CH(OH)COO⁻] = n (lactate) / 660 ml = 0.45 M
pH = 3.86 + log \frac{0.45 M}{0.29 M} = 3.86 + 0.191 = 4.05
So the pH of given solution is 4.05
7 0
3 years ago
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